Answer:
We would need 10 mL of the concentrated CaCl₂ stock solution, and 30 mL of water.
Explanation:
To solve the question asked we can use the C₁V₁=C₂V₂ equation, where:
We <u>solve for V₁</u>:
We would need 10 mL of the concentrated CaCl₂ stock solution, and (40-10) 30 mL of water.
M(C)=73.5 g
m(H)=4.20 g
m(Cl)=72.3 g
mass of compound
m=m(C)+m(H)+m(Cl)
m=73.5+4.20+72.3=150 g
w(H)=100m(H)/m
w(H)=100*4.20/150=2.8%
w(Cl)=100m(Cl)/m
w(Cl)=100*72.3/150=48.2%
w(C)=100-w(H)-w(Cl)
w(C)=100-2.8-48.2=49.0%
Answer:
Explanation:
1. It is not Blanced. on the right the is 1S and 6O and the left there is 1S and 3O
2.If the energy level of the reactants is higher than the energy level of the products the reaction is exothermic (energy has been released during the reaction). If the energy level of the products is higher than the energy level of the reactants it is an endothermic reaction.
To the OH- from the ztrong base to form water and salt
Answer:
Freezing point = 1.25
Explanation:
If we increase the concentration of the solution, the concentration of H+ does not change.
Convert 2.5% in to decimal
2.5% = 2.5 ÷100
= 0.025
The freezing point = 0.025 × 50
= 1.25