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Tju [1.3M]
4 years ago
13

A redox reaction is set up so that both half reactions take place in separate beakers that are connected by a salt bridge and a

wire. A path for the transfer of ions is provided by the? (1) anode (2) cathode (3) salt bridge (4) wire
Chemistry
1 answer:
stealth61 [152]4 years ago
5 0

Answer:

Salt bridge

Explanation:

Salt bridge is used in an electrolytic cell to transfer electrons from the anode to the cathode.

Salt bridge are used because they do not interfere with the constituents of the cell I.e the anode (+very electrode) and cathode(-ve electrode).

Examples of salt bridges are AgNO₃, KCl etc.

Salt bridge can be described as a tool used to link the oxidation half cell and reduction half cell in an electrolytic set-up or galvanic cell.

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When metals, non metals,and metallics are composed according to luster, which is best description of the appearance of metalloid
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Answer:

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Explanation:

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3 years ago
A student is given the question: "what is the mass of a gold bar that is 7.379 × 10–4 m3 in volume? the density of gold is 19.3
IRINA_888 [86]

<em>The mass of a gold bar  = 1.424 x 10⁴ gram</em>

<em></em>

<h3><em>Further Explanation</em></h3>

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than type

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

\large{\boxed{{\bold{\rho~=~\frac{m}{V}}}}

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

The mass itself is often equated with weight, even though it is different. Mass is the amount of matter in the matter while weight is related to the gravitational force

<em>Known variable</em>

volume gold bar 7.379 × 10⁻⁴ m³

a density of 19.3 g/cm³

<em>Asked</em>

the mass of a gold bar

<em>Answer</em>

volume is known to be 7.379 × 10⁻⁴ m³, then we change it first to units of cm³ adjusting to units of density

7.379 × 10⁻⁴ m³ = 7.379 × 10² cm³

then:

mass = volume x density

mass = 7.379 × 10² cm³ x 19.3 g/cm³

mass = 1.424 x 10⁴ gram

<h3><em>Learn more </em></h3>

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Keywords: density, mass, volume, a gold bar

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