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Gnoma [55]
4 years ago
8

If the volume of a box is 1,463,000 cubic millimeters, what is the volume of the box in cubic meters? (1 millimeter = 0.001 mete

r)
Mathematics
1 answer:
Stells [14]4 years ago
8 0

Answer:

The volume of the box would be  0.001463 cubic meters

Step-by-step explanation:

You first have to to do the conversion from cubic milimiters to cubic meters using the rule given. A cubic milimiter is only 1^3 = or 1*1*1. We transform then this rule so it applies for cubic measures.

1 millimeter = 0.001 meter

(1 millimeter)^3 = (0.001 millimeter)^3 (raise to the cubic power)

1 cubic milimiter = (0.001*0.001*0.001) cubic meters= 0.000000001 or 1 * 10^-9 in scientific notation.

Then we us a rule of three as follows

1 cubic millimiter / 1 * 10^-9 cubic meters =1,463,000¨cubic milimiters / x cubic meters

x = 1,463,000*1 * 10^-9= 0.001463 cubic meters

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v=1/x

Step-by-step explanation:

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Pavlova-9 [17]
5 × 6,254= 31,300 is the awnser :)
6 0
4 years ago
Need help please
zlopas [31]

Answer:

B

Step-by-step explanation:

6x5=30

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8 0
2 years ago
Find all points on the x-axis that are 14 units from the point (4, -7).
BaLLatris [955]

Answer:

The points are: (16.12,0),(-8.12,0).

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

Distance between two points:

Suppose we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Find all points on the x-axis that are 14 units from the point (4, -7).

Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).

The distance is 14. So

\sqrt{(x-4)^2+(0-(-7))^2} = 14

\sqrt{x^2 - 8x + 16 + 49} = 14

\sqrt{x^2 - 8x + 65} = 14

(\sqrt{x^2 - 8x + 65})^2 = 14^2

x^2 - 8x + 65 - 196 = 0

x^2 - 8x - 131 = 0

So a = 1, b = -8, c = -131

\bigtriangleup = (-8)^{2} - 4(1)(-131) = 588

x_{1} = \frac{-(-8) + \sqrt{588}}{2} = 16.12

x_{1} = \frac{-(-8) - \sqrt{588}}{2} = -8.12

The points are: (16.12,0),(-8.12,0).

4 0
3 years ago
Add the opposite number of 1 1/5 to the sum of the numbers (−8 3/4 ) and (−2 5/6 ). Answer:
masha68 [24]

Answer:

  -12 47/60

Step-by-step explanation:

-(1 1/5) + (-8 3/4 -2 5/6) = -(1 + 8 + 2 + 1/5 + 3/4 + 5/6)

= -(11 + 12/60 +45/60 +50/60) . . . 60 is the LCD of 1/5, 3/4, 5/6

= -(11 + 107/60) . . . . . . . . . . . . . . . . add the fractions

= -(12 47/60) = -12 47/60 . . . . . . . write as a mixed number

___

Your graphing calculator may be able to do this for you. Many handle mixed numbers with ease.

4 0
3 years ago
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