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Colt1911 [192]
2 years ago
12

Describe the two dimensions of the motion of an object in a circle due to centripetal force. Explain why putting them together r

esults in circular motion g
Physics
1 answer:
mamaluj [8]2 years ago
5 0

The characteristics of cimematica we can analyze the circular motion.

  • Circular motion is the combination of perpendicular linear motions through the Pythagorean theorem.

Kinematics describes the motion of bodies, looking for relationships between position, velocity, and acceleration.

In a circular motion we can analyze it as an oscillatory motion on the x-axis and another on the y-axis, both with the same angular velocity.

              x = Aₓ cos wt

              y = A_y sin wt.

   

The resulting position can be found using the Pythagorean theorem.

             R² = x² + y ²

             R² = Aₓ² cos2 + A_y^2  sin wt

             R² = A_x^2 + A_y^2  

if the two displacements are equal, the movement is circular and if they are different, the movement is elliptical.

Consequently, a movement in several dimensions can be analyzed as several movements, one in each dimension.

In conclusion using the characteristics of cimematica we can analyze the circular motion:

  • Circular motion is the combination of linear motions through the Pythagorean theorem.

Learn more about circular motion here:  brainly.com/question/2285236

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Rudiy27

Answer:

I think the awnser is B (but don't qoute me on that)   if its right then yay but if its wrong im sorry

Explanation:

5 0
2 years ago
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Một nười thả 420g chì ở nhiệt độ 100°C và 260g nước ở nhiệt độ 58°C làm cho nước nóng lên tới 60°C . Cho nhiệt dung riêng của nư
vlabodo [156]
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2 years ago
In a flying ski jump, the skier acquires a speed of 110 km/h by racing down a steep hill and then lifts off into the air from a
matrenka [14]

Answer:

Approximately \displaystyle\rm \left[ \begin{array}{c}\rm191\; m\\\rm-191\; m\end{array}\right].

Explanation:

Consider this 45^{\circ} slope and the trajectory of the skier in a cartesian plane. Since the problem is asking for the displacement vector relative to the point of "lift off", let that particular point be the origin (0, 0).

Assume that the skier is running in the positive x-direction. The line that represents the slope shall point downwards at 45^{\circ} to the x-axis. Since this slope is connected to the ramp, it should also go through the origin. Based on these conditions, this line should be represented as y = -x.

Convert the initial speed of this diver to SI units:

\displaystyle v = \rm 110\; km\cdot h^{-1} = 110 \times \frac{1}{3.6} = 30.556\; m\cdot s^{-1}.

The question assumes that the skier is in a free-fall motion. In other words, the skier travels with a constant horizontal velocity and accelerates downwards at g (g \approx \rm -9.81\; m\cdot s^{-2} near the surface of the earth.) At t seconds after the skier goes beyond the edge of the ramp, the position of the skier will be:

  • x-coordinate: 30.556t meters (constant velocity;)
  • y-coordinate: \displaystyle -\frac{1}{2}g\cdot t^{2} = -\frac{9.81}{2}\cdot t^{2} meters (constant acceleration with an initial vertical velocity of zero.)

To eliminate t from this expression, solve the equation between t and x for t. That is: express t as a function of x.

x = 30.556\;t\implies \displaystyle t = \frac{x}{30.556}.

Replace the t in the equation of y with this expression:

\begin{aligned} y = &-\frac{9.81}{2}\cdot t^{2}\\ &= -\frac{9.81}{2} \cdot \left(\frac{x}{30.556}\right)^{2}\\&= -0.0052535\;x^{2}\end{aligned}.

Plot the two functions:

  • y = -x,
  • \displaystyle y= -0.0052535\;x^{2},

and look for their intersection. Refer to the diagram attached.

Alternatively, equate the two expressions of y (right-hand side of the equation, the part where y is expressed as a function of x.)

-0.0052535\;x^{2} = -x,

\implies x = 190.35.

The value of y can be found by evaluating either equation at this particular x-value: x = 190.35.

y = -190.35.

The position vector of a point (x, y) on a cartesian plane is \displaystyle \left[\begin{array}{l}x \\ y\end{array}\right]. The coordinates of this skier is approximately (190.35, -190.35). The position vector of this skier will be \displaystyle\rm \left[ \begin{array}{c}\rm191\\\rm-191\end{array}\right]. Keep in mind that both numbers in this vectors are in meters.

4 0
3 years ago
Which statement about oceans is incorrect?
Hitman42 [59]
It is C because less than one percent of water is fresh water
7 0
2 years ago
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the bal
RideAnS [48]

The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

v=u+gt

v=0+9.81×2.8

v=27.468 m/s

now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

5 0
2 years ago
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