Describe the two dimensions of the motion of an object in a circle due to centripetal force. Explain why putting them together r
1 answer:
The characteristics of cimematica we can analyze the circular motion.
- Circular motion is the combination of perpendicular linear motions through the Pythagorean theorem.
Kinematics describes the motion of bodies, looking for relationships between position, velocity, and acceleration.
In a circular motion we can analyze it as an oscillatory motion on the x-axis and another on the y-axis, both with the same angular velocity.
x = Aₓ cos wt
y = A_y sin wt.
The resulting position can be found using the Pythagorean theorem.
R² = x² + y ²
R² = Aₓ² cos2 + sin wt
R² =
if the two displacements are equal, the movement is circular and if they are different, the movement is elliptical.
Consequently, a movement in several dimensions can be analyzed as several movements, one in each dimension.
In conclusion using the characteristics of cimematica we can analyze the circular motion:
- Circular motion is the combination of linear motions through the Pythagorean theorem.
Learn more about circular motion here: brainly.com/question/2285236
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Answer:
The speed of the airplane relative to the air is 209.47km/hr
Explanation:
Whenever we are solving a physics problem, it's really useful to start by drawing a diagram of the problem (See picture attached). It will help us visualize the problem better.
Now, we know that the plane flew for an amount of time of 15 minutes. For our dimensions to be the same, we need to turn those 15min to hours, like this:
Once our time is rewritten as hours, we can now calculate the velocity towards north of the plane.
the plane traveled a distance to the north of 48km so the velocity is:
so
V=192km/hr j
Now, we can calculate the x and y-components of the velocity of the wind. The problem states that the wind is blowing at 42km/hr at an angle of 19° south of east, so the x and y-components of the velocity of the wind are:
and
So the velocity of the wind can be expressed as a vector as:
Once we know this, we can find the velocity of the plane with respect of the wind on x and on y:
and
So the velocity of the plane with respect to the wind can be rewritten as:
Since the problem asks us to find the speed of the plane with respect to the wind, this means that we need to find the magnitude of the velocity, since the speed is a scalar defined to be the magnitude of the velocity.
so:
speed= 209.47 km/hr
Therefore, the speed of the airplane relative to the air is 209.47km/hr
