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Colt1911 [192]
2 years ago
12

Describe the two dimensions of the motion of an object in a circle due to centripetal force. Explain why putting them together r

esults in circular motion g
Physics
1 answer:
mamaluj [8]2 years ago
5 0

The characteristics of cimematica we can analyze the circular motion.

  • Circular motion is the combination of perpendicular linear motions through the Pythagorean theorem.

Kinematics describes the motion of bodies, looking for relationships between position, velocity, and acceleration.

In a circular motion we can analyze it as an oscillatory motion on the x-axis and another on the y-axis, both with the same angular velocity.

              x = Aₓ cos wt

              y = A_y sin wt.

   

The resulting position can be found using the Pythagorean theorem.

             R² = x² + y ²

             R² = Aₓ² cos2 + A_y^2  sin wt

             R² = A_x^2 + A_y^2  

if the two displacements are equal, the movement is circular and if they are different, the movement is elliptical.

Consequently, a movement in several dimensions can be analyzed as several movements, one in each dimension.

In conclusion using the characteristics of cimematica we can analyze the circular motion:

  • Circular motion is the combination of linear motions through the Pythagorean theorem.

Learn more about circular motion here:  brainly.com/question/2285236

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The horizontal force is m*v²/Lh, where m is the total mass. The vertical force is the total weight (233 + 840)N. 

<span>Fx = [(233 + 840)/g]*v²/7.5 </span>

<span>v = 32.3*2*π*7.5/60 m/s = 25.37 m/s </span>

<span>The horizontal component of force from the cables is Th + Ti*sin40º and the vertical component of force from the cable is Ta*cos40º </span>

<span>Thh horizontal and vertical forces must balance each other. First the vertical components: </span>

<span>233 + 840 = Ti*cos40º </span>

<span>solve for Ti. (This is the answer to the part b) </span>

<span>Horizontally </span>

<span>[(233 + 840)/g]*v²/7.5 = Th + Ti*sin40º </span>

<span>Solve for Th </span>

<span>Th = [(233 + 840)/g]*v²/7.5 - Ti*sin40º </span>

<span>using v and Ti computed above.</span>
3 0
3 years ago
If the man has initial velocity of 0.4 m/s, acceleration is 0.343 m/s^2, a time of 5.8 seconds, and experimental final velocity
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Answer:

The answer is going to be C.

Explanation:

Trust me. Im an expert in physics

6 0
3 years ago
n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
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Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

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3 years ago
For high and low tides differences would they be caused by the moon and how?
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The moon has a small amount of gravity. Low tides mean the moon is not pulling on the water. High tides mean that the moon is pulling on the water.
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