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Colt1911 [192]
2 years ago
12

Describe the two dimensions of the motion of an object in a circle due to centripetal force. Explain why putting them together r

esults in circular motion g
Physics
1 answer:
mamaluj [8]2 years ago
5 0

The characteristics of cimematica we can analyze the circular motion.

  • Circular motion is the combination of perpendicular linear motions through the Pythagorean theorem.

Kinematics describes the motion of bodies, looking for relationships between position, velocity, and acceleration.

In a circular motion we can analyze it as an oscillatory motion on the x-axis and another on the y-axis, both with the same angular velocity.

              x = Aₓ cos wt

              y = A_y sin wt.

   

The resulting position can be found using the Pythagorean theorem.

             R² = x² + y ²

             R² = Aₓ² cos2 + A_y^2  sin wt

             R² = A_x^2 + A_y^2  

if the two displacements are equal, the movement is circular and if they are different, the movement is elliptical.

Consequently, a movement in several dimensions can be analyzed as several movements, one in each dimension.

In conclusion using the characteristics of cimematica we can analyze the circular motion:

  • Circular motion is the combination of linear motions through the Pythagorean theorem.

Learn more about circular motion here:  brainly.com/question/2285236

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Calculate the average speed in metres per second from Glasgow to Edinburgh
mariarad [96]
This is the same question as the one previously but with more details, so I will just use my previous answer.

1800 to 1820 is 20 minutes.1830 to 1838 is 8 minutes.1840 to 1905 is 25 minutes.
The total time travelled is 20+8+25 = 53 minutes = 3180 seconds.
The distance between Glasgow and Edinburgh is 28 + 12 + 34 = 74 km = 74000 m.

So, the average speed is 74000m/3180s = 23.27 m/s (4 s.f.)
5 0
3 years ago
John runs 120 meters in 10 seconds and then runs back to where he started in another 10 seconds. Which statement is true? Rememb
atroni [7]

Answer:

B

Explanation:

<em>A. His speed is 0 m/s </em>

<em>B. His velocity is 12 m/s </em>

<em>C. His velocity is 0 m/s </em>

<em>D. His acceleration is 12 m/s</em>

Total distance traveled by John = 120 + 120 = 240 meters

Total time taken by John to cover the distance = 10 + 10 = 20 s

<em>Average speed of John = total distance traveled/total time taken</em>

      = 240/20 = 12 m/s

Hence, the average speed/velocity of John throughout the journey is 12 m/s.

The correct option is B.

4 0
3 years ago
After being struck by a bowling ball, a 1.3 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.3 kg
GuDViN [60]

Answer:

a) 4.2m/s

b) 5.0m/s

Explanation:

This problem is solved using the principle of conservation of linear momentum which states that in a closed system of colliding bodies, the sum of the total momenta before collision is equal to the sum of the total momenta after collision.

The problem is also an illustration of elastic collision where there is no loss in kinetic energy.

Equation (1) is a mathematical representation of the the principle of conservation of linear momentum for two colliding bodies of masses m_1 and m_2 whose respective velocities before collision are u_1 and u_2;

m_1u_1+m_2u_2=m_1v_1+m_2v_2..............(1)

where v_1 and v_2 are their respective velocities after collision.

Given;

m_1=1.3kg\\u_1=5m/s\\m_2=1.3kg\\u_2=0m/s

Note that u_2=0 because the second mass m_2 was at rest before the collision.

Also, since the two masses are equal, we can say that m_1=m_2=m so that equation (1) is reduced as follows;

mu_1+mu_2=mv_1+mv_2\\\\m(u_1+u_2)=m(v_1+v_2)..............(2)

m cancels out of both sides of equation (2), and we obtain the following;

u_1+u_2=v_1+v_2.............(3)

a) When v_1=0.8m/s, we obtain the following by equation(3)

5+0=0.8+v_2\\hence\\v_2=5-0.8\\v_2=4.2m/s

b) As m_1 stops moving v_1=0, therefore,

5+0=0+v_2\\v_2=5m/s

5 0
3 years ago
What are some ways that seed dispersal can happen
Leno4ka [110]
Seeds can blow off plants in the wind and pollinate through air travel
8 0
3 years ago
Read 2 more answers
Daniel and Christopher were on a plane traveling at a velocity of 200 km/hr south for 1,000 km. How long (in hours) was the plan
docker41 [41]
Answer:
5 hours

step-by-step explanation:
very simple just divide 1,000 and 200 to get 5
3 0
3 years ago
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