Answer:
None of the options are correct. The correct answer is 30020J
Explanation:
Data obtained from the question include:
Mass (M) = 2000g
Initial temperature (T1) = 10°C
Final temperature (T2) = 29°C
Change in temperature (ΔT) = T2 - T1 = 29°C - 10°C = 19°C
Heat (Q) =?
Specific heat capacity (C) of granite = 0.79J/g°C
Applying the equation Q = MCΔT, the heat absorbed by the granite rock can be obtained as follow:
Q = MCΔT
Q = 2000 x 0.79 x 19
Q = 30020J
Answer:
0.18 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm, R = 0.083 L.atm/K.mol
Substitute these values into equation 2
n = (0.8316×5.3)/(0.083×295)
n = 0.18 moles
Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
The reactants are methane and oxygen.
The products are carbon dioxide and water.
Answer:
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