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mojhsa [17]
3 years ago
7

For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the

rate constant at 666 K is 8.28×10-3 /s. The activation energy for the gas phase decomposition of 1-bromopropane is
Chemistry
1 answer:
Radda [10]3 years ago
6 0

Answer is: activation energy of this reaction is 212,01975 kJ/mol.<span>
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁).<span>
k</span>₁ = 0,000643 1/s.<span>
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

<span> 1/T</span>₁ = 1/622 K = 0,0016 1/K.<span>
1/T</span>₂ = 1/666 K = 0,0015 1/K.<span>
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol </span>· (-0,0001 1/K).<span>
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

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<h3>What is the nitrogen cycle?</h3>

It is the biogeochemical circuit that supplies nitrogen to living things and keeps it circulating in the biosphere.

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5 0
3 years ago
The ksp of lead(ii) hydroxide, pb(oh)2, is 1.43 × 10-20. calculate the solubility of this compound in g/l.
antiseptic1488 [7]
When Pb(OH)₂ dissolves it dissociates as follows;
Pb(OH)₂ ---> Pb²⁺ + 2OH⁻
molar solubility is the number of moles of compound that can be dissolved in 1 L of solution.
if molar solubility of Pb(OH)₂ is x then molar solubility of Pb²⁺ is x and OH⁻ is 2x
the formula for solubility product constant is as follows;
ksp = [Pb²⁺][OH⁻]²
ksp = (x)(2x)²
ksp = 4x³
ksp = 1.43 x 10⁻²⁰
4x³ = 1.43 x 10⁻²⁰
x = 1.53 x 10⁻⁷ M
molar solubility of Pb(OH)₂ is 1.53 x 10⁻⁷ M
molar mass is 241.2 g/mol 
solubility of Pb(OH)₂ is 1.53 x 10⁻⁷ M x 241.2 g/mol = 3.69 x 10⁻⁵ g/L
5 0
3 years ago
Draw the structures of the following and write out their names :
german

Answer:

i. CH2 = C(CH3)CH=C(Cl) - CH3

<u> 4-methyl pent-2,4-diene-2-chloro</u>

Explanation:

ii.CH3 CH2 C(CH3) Cl CH(CH3) C(Br)2 CH3

2-Bromo -4 chloro-2,3,4 tri methyl hexane

6 0
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What is the oxidation number for Zn(OH)4 2-?
AleksAgata [21]
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