1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luden [163]
4 years ago
14

Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d

istance did he cover? what was his diplacement?
Physics
1 answer:
lord [1]4 years ago
6 0

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

d = d_1 + d_2 + d_3

d = 7 km + 5 km + 1 km

d = 13 km

Now in order to find the displacement we will show all with their directions

\vec d_1 = 7 + 5 = 12 km towards North

\vec d_2 = 1 km towards East

So total displacement is

\vec d = \vec d_1 + \vec d_2

\vec d = 12 \hat j + 1 \hat i

so net displacement will be

d = \sqrt{12^2 + 1^2} = 12.04 km

so displacement is 12.04 km

You might be interested in
Suppose you designed a spacecraft to work by photon pressure. The sail was a completely absorbing fabric of area 1.0 km2 and you
Alekssandra [29.7K]

Answer:

(a) F = 6.14 *10⁻⁴ N

(b) P = 6.14* 10⁻¹⁰ Pa

(c) t = 27.2 min

Explanation:

Area of sail A = 1.0 km² = 1.0 * 10⁶m²

Wavelength of light  λ = 650 nm = 650 * 10⁻⁹ m

Rate of impact of photons R = 1 mol/s = 6.022 * 10²³ photons/s

(a)

Momentum of each photon is Ρ = h/λ = 6.625 * 10⁻³⁴ / 650 * 10⁻⁹

      = 1.0192 * 10⁻²⁷ kg.m/s

Since the photons are absorbed completely, in every collision the above momentum is transferred to the sail.  

Momentum transferred to the sail per second is product of rate of impact of photons and momentum transferred by each photon.

dp/dt = R * h/ λ

This is the force acting on the sail.

F = R * h/λ = 6.022 * 10²³ * 1.0192 * 10⁻²⁷ = 6.14 *10⁻⁴ N

F = 6.14 *10⁻⁴ N

b)

Pressure exerted by the radiation on the sail = Force acting on the sail / Area of the sail

P = F/A =  6.14 * 10⁻⁴ / 1.0 * 10⁶ =  6.14* 10⁻¹⁰ Pa

P = 6.14* 10⁻¹⁰ Pa

c)  

Acceleration of spacecraft a = F/m = 6.14 * 10⁻⁴ /1.0 = 6.14 * 10⁻⁴m/s²

As the spacecraft starts from rest, initial speed u=0,m/s ,

final speed is u = 1.0 m/s after time t  

v = u+at  

t = 1.0 - 0/ 6.14 * 10⁻⁴ =  1629s = 27.2 min

t = 27.2 min

4 0
4 years ago
in December which will have a longer day length a country im notheren hemisphere or southern hemisphere​
astra-53 [7]

Answer:

Southern Hemisphere

Explanation:

3 0
3 years ago
A lightbulb has a resistance of 195 Ω and carries a current of 0.62 A.
ki77a [65]

Answer:

75

Explanation:

Power is current times voltage:

P = IV

Voltage is current times resistance:

V = IR

Therefore:

P = I²R

Given I = 0.62 A and R = 195 Ω:

P = (0.62 A)² (195 Ω)

P ≈ 75 W

8 0
3 years ago
A 5.0 kg bucket of water is raised from a well by a rope. If the upward acceleration of the bucket is 3.0 m/s^2, find the force
Harman [31]
We know that m = 5 kg 
                      a  =  3.0 m/s^2
                      g = 9.8 (since not written, lets assume it's an international standard) 

T - mg =  ma

T = mg + ma

T = (5 . 9.8)  +  (5 . 3 )   

T = 49 + 15
  
T  = 64 N

Hope this helps

3 0
3 years ago
Read 2 more answers
The mass of Tesla Model S is 2000 kg and its engine produces
yulyashka [42]

Answer:

The ratio of the power generated by the engines are \dfrac{2}{3}

(b) is correct option.

Explanation:

Given that,

Mass of Tesla = 2000 Kg

Torque = 400 Nm

Mass of Mercedes = 1.5 M Tesla

The Benz engine produces 50% more torque than the Tesla.

We need to calculate the power generated by the engines 6 seconds after a start from rest

Using formula of  power

P=F\cdot v

We know that,

v=at

v=\dfrac{F}{m}t

v=\dfrac{\tau}{mr}t

Put the value of F and v in equation (I)

P=\dfrac{\tau}{r}\times\dfrac{\tau}{mr}t

P=\dfrac{\tau^2t}{mr^2}

Here, r and t are same for both bodies.

P\propto\dfrac{\tau^2}{m}

We need to calculate the ratio of the power generated by the engines

Using formula of power

\dfrac{P_{T}}{P_{B}}=\dfrac{\tau_{T}^2}{m_{T}}\times\dfrac{m_{B}}{\tau_{B}}

Put the value into the formula

\dfrac{P_{T}}{P_{B}}=\dfrac{400^2}{2000}\times\dfrac{3000}{600^2}

\dfrac{P_{T}}{P_{B}}=\dfrac{2}{3}

Hence, The ratio of the power generated by the engines are \dfrac{2}{3}

3 0
3 years ago
Other questions:
  • More questions in the image.
    12·2 answers
  • A cat jumps from a window 3 m from ground level. Its initial speed is 3 m/s, at 30° above the horizontal. Disregard air resistan
    7·1 answer
  • If 20 joules of work is used to transfer 20 coulombs of charge through a 20 ohm resistor, the potential difference across the re
    9·2 answers
  • which of the following solids will have the highest wave speed? one that has a high level of stiffness combines with low density
    12·2 answers
  • A 90kg woman and a 60kg boy are standing at rest on a frictionless frozen lake. The boy pushes the woman with a 40N horizontal f
    7·1 answer
  • True or False<br><br> Visible light is a kind of electromagnetic wave.
    8·1 answer
  • Why might farmer plant purebred crop seeds?
    7·2 answers
  • Kind of physical barrier
    15·1 answer
  • If you make a sound by tapping on a glass of water what is the order of vibration
    7·2 answers
  • Angie, brad, and carlos are discussing a physics problem in which two identical bullets are fired with equal speeds at equal-mas
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!