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Luden [163]
3 years ago
14

Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d

istance did he cover? what was his diplacement?
Physics
1 answer:
lord [1]3 years ago
6 0

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

d = d_1 + d_2 + d_3

d = 7 km + 5 km + 1 km

d = 13 km

Now in order to find the displacement we will show all with their directions

\vec d_1 = 7 + 5 = 12 km towards North

\vec d_2 = 1 km towards East

So total displacement is

\vec d = \vec d_1 + \vec d_2

\vec d = 12 \hat j + 1 \hat i

so net displacement will be

d = \sqrt{12^2 + 1^2} = 12.04 km

so displacement is 12.04 km

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Two particles, one with charge −7.97×10−6 C and the other with charge 6.91×10−6 C, are 0.0359 m apart. What is the magnitude of
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Answer:

-384.22N

Explanation:

From Coulomb's law;

F= Kq1q2/r^2

Where;

K= constant of Coulomb's law = 9 ×10^9 Nm^2C-2

q1 and q2 = magnitudes of the both charges

r= distance of separation

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We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3
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we would be at (4,0)
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Three astronauts guide a 100 kg asteroid safely away from their space capsule. The first astronaut pushes with a 35 N force dire
svlad2 [7]

The magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

The given parameters;

  • <em>mass of the asteroid = 100 kg</em>
  • <em>force by first astronaut = 35 N, at 45 degrees below x -axis</em>
  • <em>force by second astronaut = 35 N, at 45 degrees above x-axis</em>
  • <em>force by third  astronaut = 35 N, at 0 degrees on x-axis</em>

The resultant horizontal force applied by the three astronauts on the asteroid is calculated as;

Fₓ = 35cos(45) + 35cos(45) + 35cos(0)

Fₓ = 84.5 N

The rate at which the asteroid's velocity changes is calculated as;

F = ma = m\frac{\Delta v}{\Delta t} \\\\\frac{\Delta v}{\Delta t}  = \frac{F}{m} \\\\\frac{\Delta v}{\Delta t}  = \frac{84.5}{100} \\\\\frac{\Delta v}{\Delta t}  = 0.845 \ m/s^2

Thus, the magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

Learn more here: brainly.com/question/20407089

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