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xxMikexx [17]
3 years ago
10

Suppose we measure the energy stored in some inductor to be E when there is a current I running through it. If I double the curr

ent in the inductor, the new total energy will become _____.
a. 8E
b. 2E
c. E
d. E/4
e. E/2
f. 4E
Physics
1 answer:
slavikrds [6]3 years ago
3 0

Answer:

If I double the current in the inductor, the new total energy will become 4E (option f).

Explanation:

The coil or inductor is a passive component made of an insulated wire that stores energy in the form of a magnetic field due to its form of coiled turns of wire, through a phenomenon called self-induction. In other words, inductors store energy in the form of a magnetic field. The energy stored in the space where there is a magnetic field in the inductor is:

E=\frac{1}{2} *L*I^{2}

where E is Energy [J], L is Inductance [H] and I is Current [A].

If you double the current in the inductor, then the new value of the current is I'= 2*I. So replacing the new total energy is:

E'=\frac{1}{2} *L*I'^{2}=\frac{1}{2} *L*(2*I)^{2}=\frac{1}{2} *L*4*I^{2}=4*\frac{1}{2} *L*I^{2}

Then:

E'=4*E

<em><u>If I double the current in the inductor, the new total energy will become 4E (option f).</u></em>

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2 years ago
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nikitadnepr [17]

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Answer:

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Explanation:

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Consider a small bob of mass m is tied to extensible string of length l that is fixed to rigid support. The bob is oscillating in the plane about verticle.

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Since, pendulum is in hormonic motion,

as we know, F=-kx

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From equation (1) and (2)

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\frac{2\pi}{T}=\sqrt{\frac{g}{l}

T=2\pi\sqrt{\frac{l}{g}}

6 0
3 years ago
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