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navik [9.2K]
3 years ago
15

Gasoline in a storage tank potential or kinetic?

Chemistry
2 answers:
cestrela7 [59]3 years ago
8 0
Potential because the gas is not yet in use or using energy
Xelga [282]3 years ago
7 0
Potential i believe.
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A solution of a base differs from a solution of an acid in that the solution of a base?A. is able to conduct electricity B. is a
Anon25 [30]

Answer:

  • <u><em>Option D. has a great [OH⁻]</em></u>

Explanation:

1) Both <em>acids</em> and <em>bases</em> ionize in aqueous solutions so they are able to <em>conduct electricity</em>.

The ions, being charged particles, when flow through the solution are charge carriers, then they conduct electricity.

So, the option A does not state a difference between a solution of a base and a solution of an acid.

2) Both acids and bases are able to cause an <em>indicator color change</em>.

The usufulness of the indicators is that they are able to change of color when the pH changes either from acid to basic or from basic to acid. There are different indicators because none is suitable for the whole range of pH, but the statement B is not how solutions of base and acids differ.

3) The model of Arrhenius for acids and bases states that an acid is a substance that ionizes in water releasing H⁺ ions (this is equivalent to H₃O⁺) and a base is a substance that releases OH⁻ ions in water. Then, acids have a greater concentration of H₃O⁺ (so option C is not true for a solution of a base) and bases  have a greater concentraion of OH⁻, making the option D. true.

8 0
3 years ago
A) 2Fe(s) + O2(g) =&gt;
TiliK225 [7]

Answer:  -22.2 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps. SGDSDGSDGSDGgsg

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(1)  2Fe(s)+O_2(g)\rightarrow 2FeO(s)  \Delta H_1=-544.0kJ

(2)  4Fe(s)+O_2(g)\rightarrow 2Fe_2O_3(s)  \Delta H_2=-1648.4kJ

(3)  Fe_3O_4(s)\rightarrow 3Fe(s)+2O_2(g)  \Delta H=+1118.4kJ

Reversing 1 ,2 and 3 and halving 1 and 2 and then adding we get net equation:

(4) Fe_2O_3(s)+FeO(s)\rightarrow Fe_3O_4(s)  \Delta H_4=?

\Delta H_4=\frac{-\Delta H_1}{2}+\frac{-\Delta H_2}{2}+(-\Delta H_3)=\frac{544.0}{2}+\frac{1648.4}{2}+(-1118.4)=-22.2kJ

Therefore, the heat of reaction, ΔH, for the reaction is -22.2 kJ

6 0
3 years ago
If you flow a solution of Mg CO3-- in water over a Cation resin, what will be in the outlet stream leaving the bed
vodka [1.7K]

In a a cation-exchange resin, the outlet stream leaving the bed will contain H^{+} and CO_3 ^{2-}.

<h3>What is cation-exchange resin?</h3>
  • A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or cation-exchange resin.
  • It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or yellowish in color.
  • The process is known as cation-exchange resin because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions.
  • cation-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins. Many diverse separation, purification, and decontamination techniques use cation-exchange resin.
  • The most typical examples are water filtration and water softening.

To learn more about cation-exchange resin with the given link

brainly.com/question/21052225

#SPJ4

8 0
2 years ago
what is the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22c to 66c
aniked [119]

Answer :

the amount of heat,in joules, required to increase the temperature of a 49.5-gram sample of wanted from 22°c to 66°c is 9.104 Joules.

Explanation:

The answer can be calculated using the formula

Q = mCрΔT

where

Q is the amount of heat required in joules to raise the temperature.

m is the mass of the sample in Kg.

Cp is the specific heat of the sample in J/Kg°C.

ΔT is the change in temperature required.

Here, m = 49.5-gram = 0.0495 kg

Cp = 4.18 J/Kg°C (for water)

T₁ = 22°C  ; T₂ = 66°C

ΔT =  66 - 22 = 44

Substituting values in Q = mCрΔT

Q = (0.0495)(4.18)(44)

                  Q = 9.104 J

5 0
3 years ago
CH4 + 2O2 —&gt; 2H2O + CO2
Dovator [93]

Answer:  20 mol CH4 x 1CO2 / 1CH4 = 20mol  CO2

Answer: 20mol CO2

Explanation:

4 0
3 years ago
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