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vitfil [10]
3 years ago
6

You are on a building with a snowball. You see your favorite physics teacher walking by about 10 m away from you. How fast must

you throw the snow ball to hit him (assume you hit him on the foot and you throw the snow ball horizontally from a height of 5.5m)
Physics
1 answer:
tankabanditka [31]3 years ago
5 0

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Explanation:

You throw the snow ball horizontally from a height 5.5 meters

Your favorite physics teacher is 10 m away from you

You hit him on the foot

1. The initial velocity of the ball is v

2. The vertical component of v is zero because you throw the ball

     horizontally

3. The vertical distance h is 5.5 m

4. The horizontal distance x is 10 m

We need to find how fast you must throw the snow ball to hit him

→ h = v_{y} t + \frac{1}{2} g t²

→ h = -5.5 m ⇒ height below the point of thrown

→ g = -9.8 m/s²

→  v_{y} = 0 ⇒ vertical component of v

→ -5.5 = (0) t + \frac{1}{2} (-9.8) t²

→ - 5.5 = -4.9 t²

Divide both sides by -4.9

→ t² = 1.12245

Take √ for both sides

→ t = 1.06 seconds

→ x = v_{x} t

→ v_{x} = v

→ x = 10 m , t = 1.06

→ 10 = v(1.06)

Divide both sides by 1.06

→ v = 9.43 m/s

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Learn more:

You can learn more about velocity in brainly.com/question/13103128

#LearnwithBrainly

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Oxana [17]

Answer:

A)  I_{total} = 1.44 kg m², B) moment of inertia must increase

Explanation:

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Let's apply these equations to our case

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The mass of the arms is

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