1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vitfil [10]
3 years ago
6

You are on a building with a snowball. You see your favorite physics teacher walking by about 10 m away from you. How fast must

you throw the snow ball to hit him (assume you hit him on the foot and you throw the snow ball horizontally from a height of 5.5m)
Physics
1 answer:
tankabanditka [31]3 years ago
5 0

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Explanation:

You throw the snow ball horizontally from a height 5.5 meters

Your favorite physics teacher is 10 m away from you

You hit him on the foot

1. The initial velocity of the ball is v

2. The vertical component of v is zero because you throw the ball

     horizontally

3. The vertical distance h is 5.5 m

4. The horizontal distance x is 10 m

We need to find how fast you must throw the snow ball to hit him

→ h = v_{y} t + \frac{1}{2} g t²

→ h = -5.5 m ⇒ height below the point of thrown

→ g = -9.8 m/s²

→  v_{y} = 0 ⇒ vertical component of v

→ -5.5 = (0) t + \frac{1}{2} (-9.8) t²

→ - 5.5 = -4.9 t²

Divide both sides by -4.9

→ t² = 1.12245

Take √ for both sides

→ t = 1.06 seconds

→ x = v_{x} t

→ v_{x} = v

→ x = 10 m , t = 1.06

→ 10 = v(1.06)

Divide both sides by 1.06

→ v = 9.43 m/s

You must throw the snow ball by velocity 9.43 m/s horizontally to

hit him

Learn more:

You can learn more about velocity in brainly.com/question/13103128

#LearnwithBrainly

You might be interested in
Suppose that a star has a spectrum that includes red, blue, and violet lines spaced in the pattern of the lines from hydrogen bu
ladessa [460]

Answer:

It can be concluded that the star is moving away from the observer.

Explanation:

Spectral lines will be shifted to the blue part of the spectrum if the source of the observed light is moving  toward the observer, or to the red part of the spectrum when is moving away from the observer (that is known as the Doppler effect).

The wavelength at rest for this case is 434 nm and 410 nm (\lambda_{0} = 434nm, \lambda_{0} = 410nm)

Redshift: \lambda_{measured}  >  \lambda_{0}

Blueshift: \lambda_{measured}  <  \lambda_{0}

Since, \lambda_{measured} (444nm) is greater than \lambda_{0} (434 nm) and \lambda_{measured} (420nm) is greater than \lambda_{0} (410 nm), it can be concluded that the star is moving away from the observer

6 0
3 years ago
REDDIT You look at a circular loop of wire such that the plane of the loop is perpendicular to your line of vision. The loop has
sergiy2304 [10]

Answer:

The circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.

Explanation:

Since the magnetic field, B points in my direction and the current, I is moving in a clockwise direction, the current is always perpendicular to the magnetic field and will thus experience a constant force, F = BILsinФ where Ф is the angle between B and L.

Since the magnetic field is in my direction, it is perpendicular to the plane of the circular loop and thus perpendicular to L where L = length of circular loop. Thus Ф = 90° and F = BILsin90° = BIL

According to Fleming's left-hand rule, the fore finger representing the magnetic field, the middle finger represent in the current and the thumb representing the direction of force on the circular loop.

At each point on the circular loop, the force is always directed towards the center of the loop and thus tends to compress it.

<u>So, the circular loop experiences a constant force which is always directed towards the center of the loop and tends to compress it.</u>

3 0
3 years ago
Hopping is performed on 2 feet<br><br><br> True<br> False
gizmo_the_mogwai [7]
True welcome₩₩ sorry
8 0
2 years ago
Read 2 more answers
According to the inverse square law of light, how will the apparent brightness of an object change if its distance to us triples
aleksley [76]
According to the inverse square law of light, <span>apparent brightness will decrease by a factor of 9. Use the formula </span>B=L/(4*pD^2), to check it.
4 0
3 years ago
When do vernal equinoxes usually occur? autumnal?
shepuryov [24]

Spring tides occur twice each lunar month all year long without regard to the season. Neap tides, which also occur twice a month, happen when the sun and moon are at right angles to each other. ... The moon appears full when the Earth is between the moon and the sun

7 0
3 years ago
Other questions:
  • A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are 42◦ from t
    9·1 answer
  • The human ear canal is about 2.9 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu
    13·1 answer
  • What is the value of x in the equation below 1+2e^x+1=9
    5·1 answer
  • A car has positive acceleration. What information can you infer from this? A- The car is changing direction. B- The car is speed
    6·2 answers
  • Sara wanted to paddle her canoe in the swamp to see alligators. She dragged the 45 Newton canoe for 36 seconds down the boardwal
    15·1 answer
  • Is ‘velocity’the displacement of an object during specific unit of time?
    11·2 answers
  • Question 4
    7·1 answer
  • In what direction or orientation did the man throw the ball in image A? image B?​
    10·1 answer
  • A 1.0 kg mass at the end of a spring has an amplitude of 0.10 m and vibrates 2.0 times per second. What is its velocity when it
    6·1 answer
  • A force that is doing work on a ball when that ball is falling through the air.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!