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Firstly, we need to convert 3g aspartame into moles aspartame. In order to do this we have to find the molecular mass of aspartame (the total weight of each atom of the molecule combined. This figure can be used to construct a conversion factor so that the grams may be converted into moles. Molecular weights for each atom can be found on any periodic table. Avagadro's number (6.022*10^23) is a constant value that expresses the number of molecules in one mole of a substance.
The molecular weight for aspartame is 294.3 grams per mole.
The process of finding how many atoms of H there are in 3.00g of aspartame would be like this:
1. 3g * 1mol/294.3g = .01mol aspartame (this is converting grams to moles)
2. .01mol * 6.022*10^23 = 6.022*10^21 (This is finding the number of molecules)
3. (6.022*10^21) * 18 = 1.08*10^23
This 3rd calculation is done because in part 2, you calculated the number of molecules of aspartame there were in 3g. In each molecule of aspartame there are 18 hydrogen atoms. So the final answer is:
1.08*10^23 hydrogen atoms.
Answer:
Remove the already produced water and allow the reaction to reach equilibrium again.
Explanation:
<em>According to Le Chatelier principle, when a reaction is in equilibrium and one of the factors that influence the rate of reaction is altered, the equilibrium will shift so as to annul the effects of the change.</em>
If the product is continuously being removed from a reaction that is in equilibrium, more product will continued to be formed in another to annul the effect of reduction in the concentration of product.
Hence, in order to maximize production of water in the reaction, the product (water) needs to be removed and the reaction allowed to reach equilibrium again.