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3 years ago

• A cable is suspended over a pulley. A 5.0 kg mass is attached to

Physics

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

Tension= $\frac{20g}{3}$ (g=acceleration of gravity)

Explanation:

Given that,

A 5Kg and 10Kg are attached by a cable suspended over a pulley.

As 10Kg > 5Kg , the 10 kg mass accelerates down and the 5kg mass accelerates up, let it be a. Let the tension in the cable be T.

So, the equations of motion are

$10g-T = 10a$

$T-5g=5a$

Now adding them we get,

$5g=15a$

$a=\frac{g}{3}$

Substituting them back in the equation we get,

$10g-10(\frac{g}{3} ) = T$

$T= \frac{20g}{3}$

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At the beginning of 2016, robotics inc. acquired a manufacturing facility for $13.1 million. $10.1 million of the purchase price

ki77a [65]

$ 376153 is depreciation on the building for 2018.

<u>Explanation:</u>

Given data:

Original cost = $13.1 million

Residual value = $2.1 million

Useful life = 20 -year

Depreciation on the building for 2016 = $=\frac{\text {original cost-residual value}}{\text { Useful life }}$

By substituting the given values, we get,

$=\frac{(\$ 13.1 \text { million }-\$ 2.1\text { million) } }{20 \text { years }}=\frac{11.1 \text { million }}{20 \text { years }}$ = 5500000

Depreciation for 2016 $5500000

Depreciation for 2017 $5500000

Depreciation at Dec 31, 2017 $ 5500000

In 2018, the estimates of useful life and residual value were changed to 15 years and $610000, but 2 yrs have already passed, so there're 13 more yrs to go.

Depreciation on the building for 2018,

$=\frac{\text { book value at the end of } 2016-\text {residual value}}{\text { useful life }}$

= $=\frac{\$ 5500000-\$ 610000}{13}=\frac{4890000}{13}=\$ 376153$

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3 years ago

Using a schematic diagram, explain the steps of the laser technique.

nignag [31]

The steps of the use of the laser technique is explained below:

A laser beam is emitted from the diode in the unit and spread into a laser plane (1).
The laser plane, appearing as a line on the sphere (2), is reflected and collected by dual CCD arrays (1).
The resulting 2D profile is digitized and as the unit travels along the x-axis of the object, multiple profiles are collected yielding a 3D coordinate point cloud of the surface (3).

<h3>What is a Laser Technique?</h3>

This refers to the type of surgery that makes use of special light beams in order to cut open the human body in a surgical procedure.

Hence, we can see that the laser technique is considered safer than conventional surgical methods.

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2 years ago

When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the

postnew [5]

They are experiencing the pull of leaving the atmosphere

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3 years ago

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Which types of electromagnetic wave travels through space the fastest?

viva [34]

Answer:

The electromagnetic wave that travels the fastest through space is gamma ray

Explanation:

Electromagnetic wave is a type of wave which does not require material medium for its propagation. Examples of electromagnetic waves according to increasing frequency of the waves are gamma ray, x-ray, ultra violet ray, infra red, visible light, micro wave and radio waves.

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3 years ago

A stone is thrown vertically upward with a speed of 15.5 m/s from the edge of a cliff 75.0 m high .

rjkz [21]

a) 2.64 s

We can solve this part of the problem by using the following SUVAT equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement of the stone

u is the initial velocity

t is the time

a is the acceleration

We must be careful to the signs of s, u and a. Taking upward as positive direction, we have:

- s (displacement) negative, since it is downward: so s = -75.0 m

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a= g = -9.8 m/s^2 (acceleration of gravity)

Substituting into the equation,

$-75.0 = 15.5 t -4.9t^2\\4.9t^2-15.5t-75.0 = 0$

Solving the equation, we have two solutions: t = -5.80 s and t = 2.84 s. Since the negative solution has no physical meaning, the stone reaches the bottom of the cliff 2.64 s later.

b) 10.4 m/s

The speed of the stone when it reaches the bottom of the cliff can be calculated by using the equation:

$v=u+at$

where again, we must be careful to the signs of the various quantities:

- u (initial velocity) positive, since it is upward: +15.5 m/s

- a (acceleration) negative, since it is downward: so a = g = -9.8 m/s^2

Substituting t = 2.64 s, we find the final velocity of the stone:

$v = 15.5 +(-9.8)(2.64)=-10.4 m/s$

where the negative sign means that the velocity is downward: so the speed is 10.4 m/s.

c) 4.11 s

In this case, we can use again the equation:

$s=ut+\frac{1}{2}at^2$

where

s is the displacement of the package

u is the initial velocity

t is the time

a is the acceleration

We have:

s = -105 m (vertical displacement of the package, downward so negative)

u = +5.40 m/s (initial velocity of the package, which is the same as the helicopter, upward so positive)

a = g = -9.8 m/s^2

Substituting into the equation,

$-105 = 5.40 t -4.9t^2\\4.9t^2 -5.40 t-105=0$

Which gives two solutions: t = -5.21 s and t = 4.11 s. Again, we discard the first solution since it is negative, so the package reaches the ground after

t = 4.11 seconds.

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3 years ago

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