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4 years ago

10

A car traveling at speed of 24 m/s comes to stop at the red light how much time will it take for the car to stop if its accelera

tion is -8.0 M/S2

2 answers:

Serga [27]4 years ago

8 0

Answer:

The car take the time is 3.0 sec

Explanation:

Given that,

Speed = 24 m/s

Acceleration = -8.0 m/s²

We need to calculate the time

Using equation of motion

$v = u+at$

Where, v = final velocity

u = initial velocity

a = acceleration

t = time

Put the value into the formula

$0=24-8.0\times t$

$t =\dfrac{24}{8.0}$

$t = 3.0\ sec$

Hence, The car take the time is 3.0 sec.

kirill [66]4 years ago

4 0

Use this formula:

final speed = initial speed + acceleration * time

0 = 24 - 8*t, t = 3 s! The answer is 3 seconds

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To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

$\text{Initial Energy}=\text{Final Energy}$

$\frac{1}{2} mv^2=\frac{1}{2} kx^2$

Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

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$v^2 = \frac{kx^2}{m}$

$v = \sqrt{\frac{kx^2}{m}}$

Our values are,

$m = 5.22*10^4kg$

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Replacing our values we have,

$v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}$

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4 years ago

What mathematical relationship between variables is suggested by a graph showing a diagonal line from the lower left to the uppe

Tresset [83]

Answer:

Direct proportionality

Explanation:

The graph of variables that are directly proportional such as the temperature and volume of a gas has a graph consisting of a diagonal line that from the lower left of the graph to the upper right of the graph

According to Charles law, the volume of a given mass of gas is directly proportional to its temperature in Kelvin at constant pressure

Charles law can be represented mathematically as V ∝ T

From which we have;

V₁/T₁ = V₂/T₂, therefore, the graph of V to T has a constant slope, ΔV/ΔT.

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3 years ago

A 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. Which of the following statements is true?

ella [17]

In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s

7 0

3 years ago

Read 2 more answers

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Llana [10]

Answer:

brainly plus

Explanation:

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3 years ago

Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.

KIM [24]

Answer:

The velocity is $v = 4.76 \ m/s$

Explanation:

From the question we are told that

The first distance is $d_1 = 4.0 \ km = 4000 \ m$

The first speed is $v_1 = 5.0 \ m/s$

The second distance is $d_2 = 1.0 \ km = 1000 \ m$

The second speed is $v_2 = 4.0 \ m/s$

Generally the time taken for first distance is

$t_1 = \frac{d_1 }{v_1 }$

$t_1 = \frac{4000}{5}$

$t_1 = 800 \ s$

The time taken for second distance is

$t_1 = \frac{d_2 }{v_2 }$

$t_1 = \frac{1000}{4}$

$t_1 = 250 \ s$

The total time is mathematically represented as

$t = t_1 + t_2$

=> $t = 800 + 250$

=> $t = 1050 \ s$

Generally the constant velocity that would let her finish at the same time is mathematically represented as

$v = \frac{d_1 + d_2}{t }$

=> $v = \frac{4000 + 1000}{1050 }$

=> $v = 4.76 \ m/s$

7 0

4 years ago