Answer:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
Explanation:
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In this case, considering the given data, we notice that the amino acid has a N-terminal Leu, that is why we first discard d. Moreover, considering the data (iii) and (v) we can infer that there are going to be two fragments by which it is possible to reason the proper sequence:
(iii): the amino acid has one section composed by Lys-Phe-Val-Val and another one by Ala, Arg, Leu that is why e is also discarded.
(v): the other two fragments are Ala, Arg, Leu, Phe, that is why b is discarded.
(iii) and (v): given the aforementioned fragments, we can combine them and therefore discard c, that is why the correct sequence is:
a. Leu-Ala-Arg-Phe-Val-Val-Lys
.
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The Ksp of Mg(OH)2 in water is 1.8 x 10-<span>11. This means that in pure water, Mg(OH)2 has a solubility of:
</span>∛[(1.8 x 10-11) / 4] = 1.65 x 10-4 mol/L
<span>which is equal to
</span>1.65 x 10-4<span> mol x (58.32) / 10 x 100 mL = 9.62 x 10-4g / 1x102 mL
If the pH is 12, the hydroxide concentration in the solvent is
10^-(14-12) = 0.01 mol/L
The solubility is solve using the formula
</span>1.8 x 10-11 = x (2(0.01 + x))^2
x = 4.5x10-8 mol/L
which is equal to
4.5x10-8 mol x (58.32) / 10 x 100 mL = 2.62 x 10-7g / 1x102 mL
Answer:
gravity, magnetic, electrostatic
