Answer:
1470Joules
Explanation:
Workdone = Force * distance
Since the worker pushes the crate up the 3m ramp. The distance covered is 3m
Force = Mass * Acceleration due to gravity
Force = 50*9.8
Force = 490N
Workdone = 490 * 3
Workdone = 1470Joules
Hence I did 1470Joules of work
Answer:
The international date line is measured approximately from <u><em>180 degrees longitude</em></u>.
Explanation:
Meridians and parallels are the imaginary lines used to determine degrees of latitude and geographic longitude. They differ in that the meridians are the circumferences that pass through both poles of the globe, while the parallels are the minor circles that are parallel to the equator, and which serve as the basis for determining latitude.
An antimeridian is a meridian exactly opposite to any meridian that is taken from reference, and therefore, the resulting meridian adds 180 º to that taken from reference.
The Greenwich meridian is the one from which the degrees of geographical longitude of each place on the planet are counted over the Equator. Its name is due to the fact that the imaginary line of the 0 ° meridian that passes through the two poles of the Earth crosses the English town of Greenwich.
When taking Greenwich, 0º, as its reference meridian, its antimeridian is the one located on the opposite side to 180º. This meridian is the international date change line.
So the international date change line is an imaginary surface land line drawn over the Pacific Ocean and coincident with the 180 ° meridian.
Then, <u><em>the international date line is measured approximately from 180 degrees longitude.</em></u>
Answer:
As you move across a period, the atomic mass increases because the atomic number also increases
Explanation:
When the atomic number increases, this means that there are more protons and neutrons that add to the atomic mass of an atom.
Having your space clean. have on close toed shoes. have your hair pulled back into a ponytail. keep ur work space clean. wear gloves and goggles. do not have on droopy clothes. follow the steps on the board and double check them.
Answer:
the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.
Explanation:
This problem asks that we determine whether or not a critical flaw in a wide plate is subject to detection given the limit of the flaw detection apparatus (3.0 mm), the value of KIc (98.9 MPa m), the design stress (sy/2 in which s y = 860 MPa), and Y = 1.0.
![ac=1/\pi (\frac{Klc}{Ys} )^{2}\\ ac=1/\pi(\frac{98.9}{(1)(860/2)} )^{2}\\ ac=0.0168m\\ac=16.8mm](https://tex.z-dn.net/?f=ac%3D1%2F%5Cpi%20%28%5Cfrac%7BKlc%7D%7BYs%7D%20%29%5E%7B2%7D%5C%5C%20ac%3D1%2F%5Cpi%28%5Cfrac%7B98.9%7D%7B%281%29%28860%2F2%29%7D%20%29%5E%7B2%7D%5C%5C%20%20ac%3D0.0168m%5C%5Cac%3D16.8mm)
Therefore, the critical flaw is subject to detection since this value of ac (16.8 mm) is greater than the 3.0 mm resolution limit.