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olasank [31]
3 years ago
9

A semitrailer is coasting downhill along a mountain highway when its brakes fail. the driver pulls onto a runaway-truck ramp tha

t is inclined at an angle of 15.0° above the horizontal. the semitrailer coasts to a stop after traveling 159 m along the ramp. what was the truck's initial speed? neglect air resistance and friction
Physics
1 answer:
natima [27]3 years ago
8 0
I think it is 180 because it is heading to high
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a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at th
Elza [17]
... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s
4 0
3 years ago
A cylindrical, 0.500-m rod has a diameter of 0.02 m. The rod is stretched to a length of 0.501 m by a force of 3000 N. What is t
Salsk061 [2.6K]

Answer:

Y = 4.775 x 10⁹ Pa = 4.775 GPa

Explanation:

First, we calculate the stress on the rod:

stress = \frac{Force}{Area} = \frac{3000\ N}{\pi r^2}  \\\\stress = \frac{3000\ N}{\pi (0.01\ m)^2}\\\\stress = 9.55\ x\ 10^6\ Pa = 9.55 MPa\\

Now, we calculate the strain:

strain = \frac{Change\ in Length}{Original\ Length}\\\\strain = \frac{0.501\ m - 0.5\ m}{0.5\ m}\\\\strain =  0.002\\

Now, we will calculate the Young's Modulus (Y):

Y = \frac{stress}{strain}\\\\Y = \frac{9.55\ x\ 10^6\ Pa}{0.002} \\

<u>Y = 4.775 x 10⁹ Pa = 4.775 GPa</u>

6 0
3 years ago
An object moving forward at 10 m/s suddenly begins moving backward at 5 m/s. What is the most accurate explanation for this chan
Vinil7 [7]
My best guess would be C.
8 0
3 years ago
Read 2 more answers
Si se tiene un gato hidráulico y se aplica una fuerza en el Area 1, se refleja otra fuerza en el Area 2, teniendo en cuenta la s
iren [92.7K]

Answer:

the forces are proportional to their areas of application

Explanation:

In a hydraulic jack, Pascal's principle is used, that the pressure in an incompressible liquid is the same at the same height, whereby the pressure on both sides of the jack are the same

           P₁ = P₂

the pressure is defined by

            P = F / A

we substitute

           \frac{F_1}{A_1}  = \frac{F_2}{A_2}

           F₂ = \frac{A_2}{A_1} \ F_1

therefore the force is F₂> F₁

Therefore the forces are proportional to their areas of application

7 0
4 years ago
An object of mass m is traveling around a circle of radius v. What happens to the centripetal force if the radius is cut in half
german

Answer:

Centripetal force doubles

Explanation:

Since centripetal force is given by

F=\frac {mv^{2}}{r}

Where F is the centripetal force, m is the mass, v is the centripetal velocity and r is circle radius.

When the radius is reduced to half then the centripetal force will be

F=\frac {mv^{2}}{0.5r}=\frac {2mv^{2}}{r}

Evidently, the centripetal force is doubled compared to the initial.

Note that while the question gives letter v for radius, I used v for velocity and r for radius since these are the standard letters for abbreviating formula of centripetal force.

7 0
3 years ago
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