Answer:
Their kinetic energy will increase but potential energy will decrease.
Explanation:
Given that
Initial velocities of electron and proton is zero.
We know that ,electron have negative charge and proton have positive charge it means that they will attract to each other.We know that opposite charge attract to each other and same charge repels to each other.
It means that the velocities of proton and electron will increase and that leads to increase in the kinetic energy of proton and electron.
We know that potential energy U

So when r will decrease then U will increase but in negative direction it means that U will decrease.
So we can say that their kinetic energy will increase but potential energy will decrease.
The electrostatic force between two charges Q1 and q is given by

where
ke is the Coulomb's constant
Q1 is the first charge
q is the second charge
r is the distance between the two charges
Re-arranging the formula, we have

and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
Answer : Zamir's displacement and Talia's displacement is equal.
Explanation :
Displacement is explained to be the changing position of an object.
Zamir covers total distance 27 m and Talia covers total distance 19 m but Zamir's initial and final position and Talia's initial and final position is same.
So, we can say that Zamir's displacement and Talia's displacement is equal.
I think its <u>B</u> because it looks like it might indicate a future rain storm.
Answer:
1) The speed of sound increases
2) 440 Hz
3) 29°C
4) 17°C
5) 434 Hz
6) 12 m/s
7) 17.3 m
Explanation:
1) The speed of sound increases
2) V = f×λ
f = V/λ = 343/0.78 = 439.744 ≈ 440 Hz
3) V = f×λ
512 × 0.68 = 348.16 m/s
348.16 - 331 = 17.16
T = 17.16/0.6 = 28.6 ≈ 29°C
4) Increase in speed = 350 - 340 = 10
Increase in temperature = 10/0.6 = 16.67° ≈ 17°C
5) f = V/λ = 343/0.79 = 434 Hz
6) 331 + 0.6×30 - (331 × 0.6 ×10) = 12 m/s
7) V = 331 + 0.6×25 = 346m/s
λ = 346/20 = 17.3 m