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Taya2010 [7]
3 years ago
6

Which of the following is an example of velocity? Question 15 options: A plane travelling south towards the Bahamas. A man runni

ng 7 miles per hour west. A car sitting at a stop sign? A dog running at 5 miles per hour.
Chemistry
2 answers:
Rasek [7]3 years ago
7 0

Answer: A man running 7 miles per hour west.

Explanation: Vector quantity is a quantity which has both magnitude and direction.

Scalar quantity is a quantity which has only magnitude.

Velocity is a vector quantity which expresses the speed of the body along with the direction in which it is moving.

v=\frac{distance}{time}=\frac{miles}{hour}

Thus the correct option is A man running 7 miles per hour west.  

ad-work [718]3 years ago
6 0

Answer is: A man running 7 miles per hour west.

Velocity is equivalent to a specification of its speed and direction of motion, for example 100 km/h to the east.

Velocity is a physical vector quantity (measured in metres per second) and need magnitude and direction to define it, for example 100 metres per second east.

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Write the ions present in a solution of k3po4. express your answers as chemical formulas separated by a comma. offset subscripts
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K₃PO₄ → 3K⁺ + PO₄³⁻

PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻

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5 0
3 years ago
In an experiment to determine the empirical formula of magnesium chloride, 0.50 g of magnesium ribbon was taken in a beaker and
Neporo4naja [7]

Answer:

The the empirical formula for magnesium chloride based on this experiment will be MgCl_{2}

Explanation:

Given that,

Mass of Mg = 0.50 g

Mass of magnesium chloride found = 1.99 g

Let the formula of magnesium chloride be Mg_{x}Cl_{y}

We know that,

Molar mass of Mg= 24 g/mol

Molar mass of magnesium chloride = (24x+35.5y) g/mol

We need to calculate the moles of Mg

Using formula of moles

Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ Mg}

Put the value into the formula

Number\ of\ moles=\dfrac{0.50}{24}

Number\ of\ moles=0.020\ mole

We need to calculate the mole of magnesium chloride

Using formula of moles

Number\ of\ moles=\dfrac{mass}{molar\ mass\ of\ magnesium\ chloride}

Put the value into the formula

Number\ of\ moles=\dfrac{1.99}{24x+35.5y}\ mole

The reaction will be,

Mg+HCl\Rightarrow Mg_{x}Cl_{y}+H_{2}

We need to calculate the value of x and y

Using number of moles of Mg in reactant and product

Moles of Mg atom in reactant=Moles of Mg atom in product

\dfrac{0.50}{24}=x\times\dfrac{1.99}{24x+35.5y}

0.020(24x+35.5y)=x\times1.99

0.48x+0.71y=1.99x

0.71y=(1.99-0.48)x

\dfrac{x}{y}=\dfrac{0.71}{1.99-0.48}

\dfrac{x}{y}=0.47\approx0.5

\dfrac{x}{y}=\dfrac{1}{2}

Hence, The the empirical formula for magnesium chloride based on this experiment will be MgCl_{2}

7 0
4 years ago
1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the veloci
jeka94

Answer:

u = 0.176 m/x

Explanation:

∴ n O2 = 1 mol

∴ mass O2 = 1 mol * 32 g/mol = 32 g

∴ T = 60°C = 333 K

∴ P = 5 bar

⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)

⇒ V = 5537.124 cm³

∴ d = 20cm

⇒ A = (1/4π)*d² = 314.16 cm²

velocity of the gas (m/x):

  • u = m / ρ*A
  • let time (t) = x sec

∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

∴ mass flow rate (m) = 32g / x

⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))

⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x

4 0
3 years ago
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