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jok3333 [9.3K]
3 years ago
14

What is a covalent bond?

Chemistry
1 answer:
Natali5045456 [20]3 years ago
4 0
A bond between two atoms that SHARE electrons
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What is the mass if 1.72 moles of sodium nitrate
alexgriva [62]

Answer:

146 g

Explanation:

Step 1. Calculate the <em>molar mass</em> of NaNO₃

Na =                    22.99

  N =                     14.01

3O = 3 × 16.00 = 48.00

               Total = 85.00 g/mol

Step 2. Calculate the <em>mass</em>  of NaNO₃

Mass of NaNO₃ = 1.72 × 85.00/1

Mass of NaNO₃ = 146 g

8 0
2 years ago
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Lithium β is a solid phase of lithium still unknown to science. The only difference between it and ordinary lithium is that Lith
pychu [463]

Answer:

The density of Lithium β is 0.5798 g/cm³

Explanation:

For a face centered cubic (FCC) structure, there are total number of 4 atoms in the unit cell.

we need to calculate the mass of these atoms because density is mass per unit volume.

Atomic mass of Lithium is 6.94 g/mol

Then we calculate the mass of four atoms;

= 4 .atoms*\frac{1.mole}{6.022 X10^{23} .atoms} *\frac{6.94g}{mole} = 4.6097 X10^{-23} g

⇒next, we estimate the volume of the unit cell in cubic centimeter

given the edge length or lattice constant a = 0.43nm

a = 0.43nm = 0.43 X 10⁻⁹ m = 0.43 X 10⁻⁹ X 10² cm = 4.3 X 10⁻⁸cm

Volume of the unit cell = a³ = (4.3 X 10⁻⁸cm)³ = 7.9507 X 10⁻²³ cm³

⇒Finally, we calculate the density of Lithium β

Density = mass/volume

Density = (4.6097 X 10⁻²³ g)/(7.9507 X 10⁻²³ cm³)

Density = 0.5798 g/cm³

3 0
3 years ago
How many formula units are in 6.12 kg of lithium nitride
BartSMP [9]
There is 213 units i believe hope so
7 0
3 years ago
During an earthquake the cooling system of a nuclear reaction can be compromise increasing the threat of what?
ohaa [14]

Explanation:

It can be compromise increasing the threat of a meltdown

7 0
3 years ago
Read 2 more answers
What quantity of sodium azide in grams is required to fill a 56.0 liters air bag with nitrogen gas at 1.00 atm and exactly 0 °C:
Margarita [4]

Answer:

108.6 g

Explanation:

  • 2NaN₃(s) → 2Na(s) + 3N₂(g)

First we use the <em>PV=nRT formula</em> to <u>calculate the number of nitrogen moles</u>:

  • P = 1.00 atm
  • V = 56.0 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 0 °C ⇒ 0 + 273.2 = 273.2 K

<u>Inputting the data</u>:

  • 1.00 atm * 56.0 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 273.2 K
  • n = 2.5 mol

Then we <u>convert 2.5 moles of N₂ into moles of NaN₃</u>, using the <em>stoichiometric coefficients of the balanced reaction</em>:

  • 2.5 mol N₂ * \frac{2molNaN_3}{3molN_2} = 1.67 mol NaN₃

Finally we <u>convert 1.67 moles of NaN₃ into grams</u>, using its <em>molar mass</em>:

  • 1.67 mol * 65 g/mol = 108.6 g
6 0
2 years ago
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