Answer:
94.57 g H2O
Explanation:
32.0 g H2
Molar Mass H2: 2.01 g/mol
84.0 g O2
Molar Mass O2: 32.00 g/mol
Molar Mass H2O: 18.02 g/mol
First balance the eqution:
2H2 + O2 = 2H2O
Find the amount of moles that both 32.0 g of H2 and 84.0 g of O2 can produce using the molar masses:
32.0 g H2 x ((1 mole H2)/ (2.015 g H2)) = 15.88 moles H2
84.0 g O2 x ((1 mole O2)/(32.00 g O2)) = 2.63 moles O2
Now you can find the amount of grams of H2O each reactant will produce:
**keep in mind of mole ratios from balanced equation**
15.88 moles H2 x ((2 moles H2O)/(2 moles H2)) x ((18.015 g H2O)/(1 mole H2O) =286.07 g H2O
2.63 moles O2 x ((2 moles H2O)/(1 mole O2)) x ((18.015 g H2O)/(1 mole H2O) = 94.76 g H2O
94.76 is the final answer because this is the limiting reactant, meaning it produces less product than the H2 so it limits the reaction from producing anymore product from the amount calculated.
Answer:
2.954 g
Explanation:
One banana contains 422 mg
One banana weighs 118 g
To make our calculations easier, we will convert both unit to the same power, that is both of them will be in g.
422 mg = 422/1000 = 0.422 g
If one banana contains 0.422 g of potassium, then 7 bananas(since he eats 1 per day) will weigh
0.422 * 7 = 2.954 g
Thus, after a week, he would have ingested at least 2.954 g of potassium.
I hope you understand the explanations. Thanks
No it will not be passed on. As the question states the moths live in a green forest so the green moths have camouflage, which is a big advantage. But the orange moth doesn’t and will very easily be spotted by predators(will die very soon probably before reaching its reproductive period) thus the mutation wont be passed on.
Hope this helps:)
Answer: Yes
Explanation: Silicon is never found as a free element naturally, meaning it always occurs with other elements.
Answer:
Va = (MbVb)/Ma
Explanation:
Divide both sides by Ma and voila!
