Answer:
T² ∝ R³
Explanation:
Given data,
The period of revolution of the planet around the sun, T
The mean distance of the planet from the sun, R
According to the III law of Kepler, " Law of Periods' states that the square of the orbital period to go around the sun once is directly proportional to the cube of the mean distance between the sun and the planet.
T² ∝ R³

From the above equation it is clear that T² varies directly as the R³.
Answer: the sun
Explanation:
The sun's radiant energy reaches the earth's surface either directly through radiation, indirectly through convection, or it can move "across" or "through" objects or materials on the surface via conduction. Let's look more closely at each case. We've probably experienced the feeling of "warmth" of the sun on our skin on a sunny day. Light energy from the sun is reaching us across space and down through the atmosphere through radiation. A dark colored vehicle in the sun quickly becomes warm (or hot!) to the touch because of radiation. The light energy from the sun heats the air in the earth's atmosphere, and this drives convection and transfers thermal energy around. It is possible that we've felt a "hot breeze" on our skin on sunny days. The thermal energy in the air will be carried to objects in its path, and it will warm them.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s
Answer:
19.3
Explanation:
Assuming we have to find Specific gravity of gold.
As we know that specific gravity is defined as the ratio of weight of the object and weight of the water displaced by the object
so it is given by
specific gravity = weight of the object/weight of the water displaced
now we have
weight of the object = (density)(volume)g
weight of object = (19.3)(0.55)g
now weight of the liquid displaced is given by
weight of water displaced = (1 g/cm^3)(0.55ml)g
now we have
specific gravity = (19.3×0.55)/(1×0.55)
specific gravity= 19.3
Answer:

Explanation:
The time taken by the light to travel a given distance is defined as:

Here c is obviously the speed of light. Now we convert the average distance form Venus to Earth to meters:

Finally, we calculate the minutes taken by the light to travel from Venus to Earth:
