Barium chlorate (ba(clo3)2) breaks down to form barium chloride and oxygen. what is the balanced equation for this reaction? whe
n counting atoms in parentheses, multiply all subscripts by the number outside the parentheses to get the number of atoms. bacl3(s) o2( g. → bacl(s) cl2(
g. o2(
g. 2baocl3(s) → 2bacl(s) cl2(
g. o2(
g. ba(clo3)2(s) → bacl2(s) o2(
g. ba(clo3)2(s) → bacl2(s) 3o2(
g. 2ba(clo3)2(s) → bacl(s) 6o2(
g. ba(clo)2(s) → bacl2(s) o2(
g.
I think the correct answer should be B<span>a(ClO3)2 = BaCl2 + 3O2. In balancing chemical reactions, it important that the number of atoms of each element in each side of the reaction should be the same. Hope this answers the question. Have a nice day.</span>
The Law of Conservation of Mass states that matter cannot be created or destroyed. Thus, the mass of substances produced in a chemical reaction is always equal to the mass of reacting substances. Therefore, there is need to have the same number of each type of element on each side of a chemical equation.
Therefore we use the coefficients of products and reactants to balance the number of atoms of an element on both sides of a chemical equation.
The equation; Ba(ClO3)2(s) = BaCl2(s) + 3 O2(s), is balanced because there is equal number of each type of element on each side of a chemical equation.
