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Ad libitum [116K]
3 years ago
11

Technician A says that the burning of the air-and-fuel mixture in the cylinder is called fuel activation. Technician B says that

the basic function of the upper-end components is to control the flow of air-and-fuel mixture into the engine and the flow of exhaust gases out of the engine after combustion. Who is right? A. Both Technicians A and B B. Technician A only C. Neither Technician A nor B D. Technician B only
Physics
2 answers:
aleksandrvk [35]3 years ago
7 0

How this answer can be Verifies if it's wrong!?!?!

irina1246 [14]3 years ago
3 0
The answer is <span>A. Both Technicians A and B</span><span>. Technician B is correct because the basic function of the upper-end components of an air-fuel mixture is to control the flow of it into the mixture. And also the statement of technician A is correct also.</span>
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The dwarf planet Ceres contains over 50% of the mass of the main asteroid belt.
PolarNik [594]

False

Explanation:

Called an asteroid for many years, Ceres is so much bigger and so different from its rocky neighbors that scientists classified it as a dwarf planet in 2006. Even though Ceres comprises 25 percent of the asteroid belt's total mass, tiny Pluto is still 14 times more massive.

6 0
2 years ago
As light shines from air to another medium, i = 42.0°. The light bends toward the normal and refracts at 38.0° What is
eduard

Answer:

1.09

Explanation:

8 0
3 years ago
uppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s
Paul [167]

Answer:

t = 22.2 s

Explanation:

angular distance covered in the 36.0 s is

θ = ω(avg)t = ½(10.0 + 30.0)36 = 720 radians

720/2 = 360 radians

α = Δω/t = (30 - 10)/36 = 5/9 rad/s²

θ = ω₀t + ½αt²

360 = 10.0t + ½(5/9)t²

   0 = (5/18)t² + 10.0t - 360

   0 = t² + 36t - 1296

t = (-36 ±√(36² - 4(1)(-1296))) / 2

t = (-36 ±√(6480)) / 2

t = -18 ±√1620

we ignore the negative time result as it occurs before we care.

t = -18 + √1620 = 22.249223... s

8 0
3 years ago
Number these from least (1) to most (5) mass ?
alisha [4.7K]

Answer:

1. A feather

2. A baseball

3. A small car

4. A truck

5. A large train

Explanation:

5 0
3 years ago
Read 2 more answers
A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

\theta=65.4^{\circ}

The projection of the length of the pendulum along the vertical direction is

L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta y = 0.211 m is the vertical displacement of the pendulum

So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

5 0
3 years ago
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