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DIA [1.3K]
3 years ago
6

Which of the following is an example of an environmental problem caused by chemicals

Chemistry
1 answer:
Neko [114]3 years ago
7 0

Answer:

A

Explanation:

All of the other options are ways that could help the environment from the chemicals, but if they just continue to use the chemicals then it would hurt the environment

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What is the mass of 3.75 moles of NaCl
sasho [114]
M (NaCl) = n × M = 3.75 × 58.5 =
219.375 g

M (NaCl) = 23 + 35.5 = 58.5 g/mol
7 0
3 years ago
Read 2 more answers
Write a brief passage describing a neutral atom of nitrogen-14 (N-14). Describe the number of protons, neutrons, and electrons i
Inessa [10]
In nitrogen-14, there are 7 protons, 7 neutrons, and 7 electrons. The protons and neutrons are in the nucleus, and the electrons are in the electron shells. The atomic number is the number of protons, the mass number is the number of protons AND neutrons, and the atomic mass is the average of the masses of all isotopes.
5 0
3 years ago
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5.77 g of nitrogen react with excess hydrogen producing 6.83 g of ammonia what is the percent yield. Determine/Label the actual
nata0808 [166]

Answer:

Percentage yield is 41.21%

Explanation:

Equation of reaction,

N₂ + 3H₂ → 2NH₃

Actual NH3 = 6.83g

Mass of N2 = 5.77g

Theoretical yield = ?

5.77g of N2 = 6.83g of NH3

14g of N2 = xg

X = (14 × 6.83) / 5.77

X = 95.62 / 5.77

X = 16.57g of NH3

Theoretical yield of NH3 is 16.57g

Percentage yield = (actual yield / theoretical yield) × 100

% yield = (6.83 / 16.57) × 100

% yield = 0.4121 × 100

% yield = 41.21%

The percentage yield of NH3 is 41.21%

6 0
3 years ago
How many total valence electrons are found in the following molecules: CO3
photoshop1234 [79]

Answer:

The Carbonate (CO2−3) Ion

Unlike O3, though, the actual structure of CO32− is an average of three resonance structures. 2. Carbon has 4 valence electrons, each oxygen has 6 valence electrons, and there are 2 more for the −2 charge. This gives 4 + (3 × 6) + 2 = 24 valence electrons

Explanation:

7 0
3 years ago
3. Crystalline structural unit of barium metal is a body-centered cubic cell. The edge length of the unit cell is 5.02x10-8 cm.
tiny-mole [99]

Answer:

The Avogadro's  number is N_A     =  6.02289 *10^{23}

Explanation:

From the question we are told that

   The edge length is  L   = 5.02 * 10^{-8} \ cm= \frac{5.02 * 10^{-8} }{100}  =  5.02 * 10^{-10}

    The density of the metal is \rho =  5.30\ g/cm^3 = 5.30 * \frac{g}{cm^3}  * \frac{1*10^6}{1*10^3} = 5.30 *10^3kg/m^3

     The molar mass of  Ba is  Z  =  137.3 \ g/mol = \frac{137.3}{1000} =  0.1373 \  kg / mol

     

Generally the volume of a unit cell is  

       V =  L^3

substituting value

        V =  [5.02 *10^{-10}]^3

         V = 1.265*10^{-28}\ m^3  

From the question we are told that 68% of the unit cell is occupied by Ba atoms and that the structure is a metal which implies that the crystalline structure will be  (BCC),

The volume of barium atom is  

        V_a  =  \frac{V}{2}  * 0.68

substituting value

        V_a  =  \frac{ 1.265*10^{-28}}{2}  * 0.68

        V_a  = 4.301 *10^{-29} \ m^3

The Molar mass of barium is mathematically represented as

      Z  =  N_A V_a *  \rho

Where N_A is the Avogadro's number

 So  

      N_A     =   \frac{ Z}{ V_a *  \rho}

substituting value

     N_A     =   \frac{ 0.1373}{ 4.301*10^{-29} *  5.3*10^{3}}

     N_A     =  6.02289 *10^{23}

4 0
3 years ago
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