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3 years ago

How much water would be needed to completely dissolve 1.78 L of the gas at a pressure of 735 torr and a temperature of 24 ∘C?

Chemistry

1 answer:

Nesterboy [21]3 years ago

4 0

Answer: 0.46L

Explanation:

KH = 0.158mol/L/atm

Pg= 735 torr = 735/760 = 0.967atm

C=?

C = KH x Pg = 0.158 x 0967

C = 0.153mol/L

T= 24°C = 24 +273 = 297K

R = 0.082atm.L/K/mol

P = 0.967atm

V = 1.78 L

n=?

PV = nRT

n = PV /RT = (0.967x1.78)/(0.082x297)

n = 0.071mol

0.153mol dissolves in 1L of water. therefore, 0.071mol will dissolve in = 0.071/0.153 = 0.46L

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Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.

Luba_88 [7]

The combined gas law equation has been $\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$ .

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

$PV=nRT$

Where, <em>P </em>has been the pressure of the gas

<em>V </em>has been the volume of the gas

<em>n </em>has been the moles of the gas

<em>R </em>has been a constant

<em>T </em>has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

7 0

3 years ago

In a reaction vessel, 17.6 g of solid chromium(III) oxide, Cr2O3, was allowed to react with excess carbon tetrachloride in the f

notsponge [240]

Answer:

72.53% is the yield of CrCl3

Explanation:

Given

Reaction:

Cr2O3(s) + 3 CCl4(l) → 2 CrCl3(s) + 3 COCl2(aq)

CCl4 is in excess and 17.6g Cr2O3 present

The reaction yields 26.6g of CrCl3

To Find:

% yields of the reaction

Also given

Molar mass of CrCl3 = 158.35g/mol

Molar mass of Cr2O3 = 152.00 g/mol

By the stoichiometry of the reaction

1 mole of Cr2O3 gives 2 moles of CrCl3

1 x1 52 g of Cr2O3 gives 2x 158.35 g of CrCl3

= 1 52 g of Cr2O3 gives 316.70 g of CrCl3

17.6 g of Cr2O3 gives (17.6÷152) × 316.70 g CrCl3

= 36.67 g CrCl3

but actual yield is only 26.6g

so % yield is (26.6 ÷÷ 36.67) × 100

= 72.53% is the yield of CrCl3

8 0

4 years ago

A sky rocket is launched with a force of 10 N and accelerates at 20 m/s squared what is the mass of this skyrocket

tia_tia [17]

Answer: 0.5 kg

Explanation:

Force of launched skyrocket = 10 N

Acceleration of skyrocket = 20 m/s squared (i.e 20m/s^2)

Mass of the skyrocket = ?

Recall that Force is the product of the mass of an object by the acceleration by which it moves.

i.e Force = Mass x Acceleration

10N = Mass x 20m/s^2

Mass = (10N/20m/s^2)

Mass = 0.5 kg

Thus, the mass of this skyrocket is 0.5 kilograms

4 0

4 years ago

Which chemical is the reducing agent in the redox reaction below?

posledela

Option (a) is correct.

A reducing agent is the one which loses electrons to other substance.

Here, Zn has oxidation number 0 in the L.H.S of the equation, but on R.H.S its oxidation number is +2 i.e. it Zn has donated two of its electrons to $Fe^{2+}$ .

Hence, Zn is the reducing agent here.

6 0

3 years ago

Boron carbonate decomposes into boron oxide and carbon dioxide. How many moles of CO2

Paul [167]

<h3>Answer:</h3>

15 moles

<h3>Explanation:</h3>

The decomposition of boron carbonate is given by the equation;

B₂(CO₃)₃(s) → B₂O₃(s) + 3CO₂(g)

Moles of boron carbonate decomposed is 5.0 mol

To find the moles of CO₂ produced we are going to use the mole ratio.

Mole ratio of B₂(CO₃)₃ to CO₂ is 1 : 3

Therefore;

Moles of CO₂ = Moles of B₂(CO₃)₃ × 3

= 15 mol

Therefore, 15 moles of CO₂ will be produced

4 0

4 years ago