Answer:
See the answer below
Explanation:
There are several scientists that contributed to the understanding of the cell. Some of them and their contributions are as follows:
Anton van Leeuwenhoek: He invented the first primitive microscope and was able to view some unicellular microscopic cells such as protozoans and bacteria. He disproved the theory of spontaneous generation by his discoveries.
Robert Hooke (1665): He improved further on the microscope invented by Leeuwenhoek and was able to view compartment-like rooms when tissues of cork were sectioned. He tagged the compartment as 'cell'.
Schleiden (1804–1881): Using an improved microscope, he was able to extensively study plant tissues and borrowed the word coined by Hooke (cell) to describe the component of the plant tissues.
Theodor Schwann (1810–1882): He studied animal tissues and made a similar observation as Schleiden.
Through their various studies, Schleiden, Schwann, and another scientist, Rudolf Virchow later developed what is nowadays known as the cell theory
8.5L H2O (1 mol H2O/22.4L)=.37946 mol H2O
.3796 mol H2O(1 mol CH4/2 mol H2O)=.18973 mol CH4
.18973 mol CH4(22.4L/1mol CH4)=4.25L CH4 gas
Answer:
6NO2+3H2O-------->3HNO2+3HNO3
Answer:
Explanation:
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In this case, since the radioactive decay equation is:
Whereas A stands for the remaining amount of this sample and A0 the initial one. In such a way, since the sample of rutherfordium is reduced to one-third of its nuclei, the following relationship is used:
And we plug it in to get:
Now, as we know its half-life, we can compute the elapsed time for such loss:
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Answer:c. At 20% efficiency, how many kWh would actually be produced from the 5 gal of gasoline? How many BTUs of heat would be released from burning the gasoline? (3 points) 1.3 x 10 J x 1 kWH / 3.6 x 10 J = 36.1 kWh 5.2 x 10 J x 1 BTU / 1055 J = 492891 BTU 36.1 kWh would actually be produced from 5 gallons of gasoline.
Explanation:
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