Newton's 2nd law of motion:
Force = (mass) x (acceleration)
Divide each side
by 'acceleration': Mass = (force) / (acceleration)
= (2,500 N) / (200 m/s²)
= 12.5 kg
D) decreases, inverse
Explanation:
The average speed of each lap decreases. This is an example of an inverse relationship.
Speed is the rate of change of distance with time. In calculating the average speed, we should understand that the total length of path is taken into consideration and so is the total time taken.
Average speed = 
It was explained that after every 5 seconds the speed of the runner becomes slower.
There is definitely an inverse relationship between average speed and the total time taken.
An inverse relationship is such that as one variable increases, the other diminishes.
As average speed reduces the time taken increases.
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C. a lot of inertia.............................. :-)
Here's an interesting fact to remember: (Period of any wave) x (Frequency of the wave) = 1 .If you can memorize that, then you'll always remember that Period = 1 / frequencyand Frequency = 1 / period. The second one is what you need for this problem. Frequency = 1 / period = 1 / (4.85 x 10⁻² second) = 1 / (0.0485 second) =20.62 / second
=20.62 Hz. (rounded)
Explanation:(Plato) I just took the test
Answer:
The time taken for the car to stop is 5.43 s.
The initial velocity of the car is 108.6 ft/s
Explanation:
The following data were obtained from the question:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Distance travalled (s) = 295 ft
Final velocity (v) = 0 ft/s
Time taken (t) =?
Initial velocity (u) =?
Next, we shall determine the initial velocity of the car as shown below:
v² = u² + 2as
0² = u² + (2 × –20 × 295)
0 = u² + (–11800)
0 = u² – 11800
Collect like terms
0 + 11800 = u²
11800 = u²
Take the square root of both side
u = √11800
u = 108.6 ft/s
Therefore, the initial velocity of the car is 108.6 ft/s.
Finally, we shall determine the time taken for the car to stop as shown below:
Acceleration (a) = –20 ft/s² (since the car is coming to rest)
Final velocity (v) = 0 ft/s
Initial velocity (u) = 108.6 ft/s
Time taken (t) =?
v = u + at
0 = 108.6 + (–20 × t)
0 = 108.6 + (–20t)
0 = 108.6 – 20t
Collect like terms
0 – 108.6 = – 20t
– 108.6 = – 20t
Divide both side by –20
t = – 108.6 / –20
t = 5.43 s
Therefore, the time taken for the car to stop is 5.43 s.
