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stellarik [79]
3 years ago
11

An object with a lot of mass has ____________.

Physics
1 answer:
aleksley [76]3 years ago
3 0
C. a lot of inertia.............................. :-)
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Daisy walks across a force platform, and forces exerted by her foot during a step are recorded. The peak velocity reaction force
Len [333]

Answer:

(a). The resultant of these forces is 1216.55 N.

(b).  The direction of the resultant forces is 80.53°.

Explanation:

Given that,

First force = 1200 N

Second force = 200 N

(a). We need to calculate the resultant of these forces

Using cosine law

F=\sqrt{F_{1}^2+F_{2}^2+2F_{1}F_{2}\cos\theta}

Put the value into the formula

F=\sqrt{1200^2+200^2+2\times1200\times200\cos90}

F=\sqrt{1200^2+200^2}

F= 1216.55\ N

The resultant of these forces is 1216.55 N.

(b). We need to calculate the direction of the resultant forces

Using formula of direction

\tan\alpha=\dfrac{F_{1}}{F_{2}}

Put the value into the formula

\alpha=\tan^{-1}(\dfrac{1200}{200})

\alpha=80.53^{\circ}

Hence, (a). The resultant of these forces is 1216.55 N.

(b).  The direction of the resultant forces is 80.53°.

4 0
4 years ago
Read 2 more answers
Two satellites are in circular orbits around a planet that has radius 9.00×106 m. One satellite has mass 68.0 kg, orbital radius
olasank [31]

Answer:

v₂ = 5131.42 m/s

Explanation:

given,

radius of the planet = r₁ = 9.00×10⁶ m

mass of the satellite = m₁ = 68 Kg

orbital radius = r₁ = 8 x 10⁷ m

orbital speed = v₁ = 4800 m/s

mass of second satellite = m₂ =  84.0 kg

orbital radius = r₂ = 7.00×10⁷ m

orbital speed of second satellite = v₂ = ?

using orbital speed of satellite

            v = \sqrt{\dfrac{GM}{r}}

     so,

            v \alpha \dfrac{1}{\sqrt{r}}

now,

            \dfrac{v_1}{v_2} =\sqrt{\dfrac{r_2}{r_1}}

            \dfrac{v_2}{4800} =\sqrt{\dfrac{8\times 10^7}{7 \times 10^7}}

                v₂ = 5131.42 m/s

The orbital speed of second satellite is equal to v₂ = 5131.42 m/s

7 0
3 years ago
You hang a heavy ball with a mass of 94 kg from a platinum rod 3.2 m long by 2.2 mm by 3.1 mm. You measure the stretch of the ro
vlada-n [284]

Answer:

1.67\times 10^{11} N/m^2

Explanation:

Mass of the ball, m=94 kg

Force = weight of the ball

F=mg = 94kg\times 9.81 m/s^2=922.14N

For Young's modulus, substitute the values in the formula which is as follows:

\frac{F}{A}=Y\frac{\Delta L}{L}\\\Rightarrow Y= \frac{FL}{A\Delta L}\\\Rightarrow Y =\frac{922.14 \times 3.2}{2.2\times 10^{-3}\times 3.1\times 10^{-3} \times 0.002588}=1.67\times 10^{11} N/m^2

4 0
3 years ago
B. ne chemical reaction involved in burning wood
balandron [24]
B. a combustion reaction involves a hydrocarbon burning with oxygen gas to produce water and carbon dioxide.
C. this is an endothermic reaction since ΔH would be positive.
3.  I am pretty sure it is referring to the activation energy which is a characteristic all chemical reaction have and in a combustion reaction the spark gets the reaction over the activation energy.
4.  K₂O(s)+CO₂(g)⇒K₂CO₃(s)+energy
The energy level of the reactants is higher than the energy level of the products (you can see this with energy diagrams).

5. 2HgO(s)+energy⇒2Hg(l)+O₂(g)
the energy levels of the products is higher than the energy level of the reactants. (this can also be seen with energy diagrams)
4 0
3 years ago
Chemistry<br> determine the pressure
sashaice [31]
I think it's 1.03412969 or 1.03
8 0
4 years ago
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