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cluponka [151]
4 years ago
14

a rock weighing 75.0g placed in a graduated cylinder displacing the volume from 31.4 ml to 36.5 ml what is density of the rock i

n grams/cubic centimeters?
Chemistry
1 answer:
andrezito [222]4 years ago
7 0
Answer:

<span>ρ≅13.0⋅g⋅m<span>L<span>−1</span></span></span> = <span>13.0⋅g⋅c<span>m<span>−3</span></span></span>

Explanation:

<span>Density=<span>MassPer unit Volume</span></span> = <span><span>75.0⋅g</span><span><span>(36.5−31.4)</span>⋅mL</span></span> <span>=??g⋅m<span>L<span>−1</span></span></span>

Note that <span>1⋅mL</span> = <span>1⋅c<span>m<span>−3</span></span></span>; these are equivalent units of volume; 
i.e. <span>1⋅c<span>m3</span></span> = <span>1×<span><span>(<span>10<span>−2</span></span>⋅m)</span>3</span>=1×<span>10<span>−6</span></span>⋅<span>m3</span>=<span>10<span>−3</span></span>⋅L=1⋅mL</span>.

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Aleonysh [2.5K]

Answer:

1. 3.83 L

2. 0.368 mole

Explanation:

1. Determination of the volume

Pressure (P) = 3.21 atm

Temperature (T) = 202 K

Number of mole (n) = 0.741 mole

Gas constant (R) = 0.0821 L.atm/molK

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The volume can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

3.21 × V = 0.741 × 0.0821 × 202

3.21 × V = 12.3497283

Divide both side by 3.21

V = 12.2888922 / 3.21

V = 3.83 L

Thus, the volume of the gas is 3.83 L

2. Determination of the number of mole.

Pressure (P) = 2.50 atm

Temperature (T) = 215 K

Volume (V) = 2.60 L

Gas constant (R) = 0.0821 L.atm/molK

Number of mole (n) =?

The number of mole can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

2.50 × 2.60 = n × 0.0821 × 215

6.5 = n × 17.6515

Divide both side by 17.6515

n = 6.5 / 17.6515

n = 0.368 mole

Thus, the number of mole of the gas is 0.368 mole.

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