How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)

2 answers:

8 0

Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L

irinina [24]3 years ago

4 0

Answer:

1.81 liters of KCl solution

Explanation:

Molarity is expressed as:

$Molarity=\frac{molesofsolute}{litersofsolution}$

Solving for Liters of solution:

Liters of solution = $\frac{molesofsolute}{Molarity}$ (1)

Using the molecular weight fo the KCl to find the moles of solute:

$15.00gKCl*\frac{1molKCl}{74.6gKCl}=0.20molesKCl$

Replacing in the formula (1):

Liters of solution = $\frac{0.20molesKCl}{0.1107M}$

Liters of solution = 1.81 liters

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