If you are in this kind of geographical scenery, you must be on a surfing beach in California. The Californian coastline is characterized by a numerous number of beaches that are mainly sandy and features major rivers such as the Sacramento River and the Colorado River.
Answer:
Northeast
Explanation:
For a person standing on a top high mid-pacific island on the 15° north latitude, the wind is expected to come from the northeast.
This is because of the Coriolis's effect. According to the Coriolis's effect the the objects moving in the northern hemisphere, tends to veer of their course to the clockwise direction. While moving clockwise from the north the east is witnessed. Thus, the wind is expected from the north east
Answer:
13520 N
Explanation:
Pascal's Principle: The principle states that the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the containing vessel.
The operation of hydraulic press and car brake system is based on pascal's principle.
From pascal's principle,
F/A = f/a ........................... Equation 1
Where F = force exerted by the large piston, A = area of the large piston, f = force applied to the small piston, area of the small piston.
Making F the subject of the equation
F = A(f/a)......................... Equation 2
Given: A = 0.13 m², a = 0.0075 m², f = 780 N
Substituting into equation 2
F = 0.13(780/0.0075)
F = 13520 N.
Thus the force exerted by the large piston = 13520 N
Answer:
Position of motorist = 33.8 m
position of police officer = 16.9 m
Explanation:
velocity of motorist, v = 13 m/s
initial velocity of police officer, u = 0
Acceleration of police officer, a = 5 m/s^2
let after time t, the velocity of police officer is equal to the velocity of motorist.
v = u + at
13 = 0 + 5 t
t = 2.6 second
Position of motorist after 2.6 second = v x t = 13 x 2.6 = 33.8 m
Position of police officer after t = 2.6 s
s = ut + 0.5 at^2
s = 0 + 0.5 x 5 x 2.6 x 2.6 = 16.9 m
Explanation:
Elongation of the wire is:
ΔL = F L₀ / (E A)
where F is the force,
L₀ is the initial length,
E is Young's modulus,
and A is the cross sectional area.
ΔL = T (0.5 m) / ((2.0×10¹¹ Pa) (0.02 cm²) (1 m / 100 cm)²)
ΔL = T (1.25×10⁻⁶ m/N)
T = (80,000 N/m) ΔL
Draw a free body diagram of the mass at the bottom of the circle. There are two forces: tension force T pulling up and weight force mg pulling down.
Sum of forces in the centripetal direction:
∑F = ma
T − mg = mv²/r
T − mg = mω²r
T − (15 kg) (9.8 m/s²) = (15 kg) (2 rev/s × 2π rad/rev)² (0.5 m + ΔL)
T − 147 N = (2368.7 N/m) (0.5 m + ΔL)
Substitute:
(80,000 N/m) ΔL − 147 N = (2368.7 N/m) (0.5 m + ΔL)
(80,000 N/m) ΔL − 147 N = 1184.35 N + (2368.7 N/m) ΔL
(797631.3 N/m) ΔL = 1331.35 N
ΔL = 0.00167 m
ΔL = 1.67 mm