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il63 [147K]
3 years ago
10

if the speed of sound through the air is rounder 80 meters per second what will be the change in temperature of the air​

Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

hope it is if the speed in air is larger by 80m/s what is change in temperature.

Explanation:

hope this helps you

............

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Which best describes two counteracting forces on an object
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The correct answer is B two children pulling apart a wishbone

Let me know if you have any questions, and have a nice day!

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3 years ago
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Prof. Kopp is working on an experiment located in an abandoned mine near Duluth, MN. The experiment is located approximately 713
MA_775_DIABLO [31]

Answer:

The average speed of the elevator going down in the abandoned mine is 17.722mph.

Explanation:

If the elevator takes 90 seconds to descend a height of 713m, the average speed of the elevator is:

v_{av}=x_T/t_T=713m/90s=7.922m/s

And if 1m/s is 2.23694mph, the average speed is:

v_{av}=7.922m/s=17.722mph.

8 0
3 years ago
Is the facceleration due to gravity the same on Earth and Earth's moon?
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Answer:

Earth's average surface gravity is about 9.8 meters per second per second. ... The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass but inversely proportional to the square of its radius.

Explanation:

3 0
3 years ago
fruit drinks are often 27 percent solutions by volume of real juice with water. If a bottle of fruit juice contains 2.00 L, what
Schach [20]
Percentage of real juice = 27% by volume.

For a 2 L juice bottle,

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5 0
3 years ago
A railroad track and a road cross at right angle. An observer stands on the road 70 meters south of the crossing and watches an
fgiga [73]

Answer:

The train is moving with a speed of 57.6 m/s.    

Explanation:

Given that,

Distance of observer from the road, d = 40 m (due south)

Velocity of the train, v = 60 m/s (due east)

So,

x(t)=70\\\\y(t)=60t

t is time

Net displacement is given by :

z(t)=\sqrt{(60t)^2+(70)^2}

Differentiating above equation wrt t as :

z'(t)=\dfrac{1}{2}(3600t^2+4900)^{-1/2}{\cdot} 7200t

Put t = 4 s

z'(4)=\dfrac{1}{2}(3600(4)^2+4900)^{-1/2}{\cdot} 7200(4)\\\\z'(4)=57.6\ m

So, the train is moving with a speed of 57.6 m/s.    

3 0
4 years ago
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