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Radda [10]
3 years ago
15

A U-shaped tube, open to the air on both ends, contains mercury. Water is poured into the left arm until the water column is 10.

0 cm deep. How far upward from its initial position does the mercury in the right arm rise?
Physics
1 answer:
Masja [62]3 years ago
8 0

Answer:

0.368 cm

Explanation:

x = distance by which the mercury rise

d = depth of the water = 10 cm = 0.10 m

ρ = density of water = 1000 kgm⁻³

ρ' = density of mercury = 13600 kgm⁻³

P₀ = atmospheric pressure

Using equilibrium of pressure on both side

P₀ + ρ g d = P₀ + ρ' g (2x)

(1000) (0.10) = (13600) (2x)

x = 0.00368 m

x = 0.368 cm

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