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Elina [12.6K]
2 years ago
7

What are four tools you can use to make quantitative observations

Physics
2 answers:
aev [14]2 years ago
8 0
Quantitative is how many or a measurement. You can take a measurement with:
a ruler
thermometer
weight scale
stop watch
Hope this helps. <span />
Maslowich2 years ago
5 0
A ruler, a bathroom scale, a clock, your heartbeat, a car speedometer, a car odometer, a photographer's light meter, a voltmeter, and a kitchen measuring cup can all deliver quantitative measurements.
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6 0
3 years ago
create a formula giving the strength of the induced field (B) i terms of current (I) and the distance from the wire to the probe
iren [92.7K]
So we need to find the formula for magnetic field B using the current (I) and the distance from the probe (d). So, We know that the stronger the current I, the stronger the magnetic field B. That tells us that the I and B are proportional. Also we know that the strength of the magnetic field B is weaker as the distance d of the probe increases. That tells us that B and d are inversely proportional. So our formula should have B=(I/d)*c where c is a constant of proportionality. c=μ₀/2π where μ₀ is the permeability of free space. So finally our formula is B=(μ₀I)/(2πd). 
6 0
2 years ago
2. In the activities below indicate if friction is useful or not useful? Explain your answer. i. Writing yes it is useful becaus
Gemiola [76]

Answer:

Please find the answer in the explanation

Explanation:

Friction is a force that opposes motion. One or two of the advantages of friction are break and ability of an object to walk.

Writing yes it is useful because when your writing because friction helps you see what your writing

ii. Rubbing. Yes, it is useful.

friction make it possible for two object to rub each other

iii. Skiing. No. It is not useful because With presence of friction, skiing will not be possible.

iv. Rotating a wheel No. It is not useful because Friction will oppose the rotation of the wheel.

8 0
3 years ago
How should scalar symbols be written? A. in bold type B. in italic type C. with an arrow on top D. in bold type or with an arrow
Gemiola [76]
D is the correct answer..........
8 0
3 years ago
The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
2 years ago
Read 2 more answers
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