Answer:
(a) T= 38.4 N
(b) m= 26.67 kg
Explanation:
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Kinematics
d= v₀t+ (1/2)*a*t² (Formula 2)
d:displacement in meters (m)
t : time in seconds (s)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
v₀=0, d=18 m , t=5 s
We apply the formula 2 to calculate the accelerations of the blocks:
d= v₀t+ (1/2)*a*t²
18= 0+ (1/2)*a*(5)²
a= (2*18) / ( 25) = 1.44 m/s²
to the right
We apply Newton's second law to the block A
∑Fx = m*ax
60-T = 15*1.44
60 - 15*1.44 = T
T = 38.4 N
We apply Newton's second law to the block B
∑Fx = m*ax
T = m*ax
38.4 = m*1.44
m= (38.4) / (1.44)
m = 26.67 kg
Answer:
no force exists by itself because every action has an equal and opposite reaction
A proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
<h3>What is speed of proton?</h3>
The speed of a proton is the rate at which a proton is moving through a given space.
The given speed of the proton is 0.99c
where;
<h3>What is speed of light?</h3>
The speed of light in vacuum, commonly denoted c, is a universal physical constant that is important in many areas of physics.
The value of speed of light in a vacuum is given as 3 x 10⁸ m/s.
The speed of the proton is calculated as follows;
v = 0.99 x 3 x 10⁸ m/s.
v = 2.97 x 10⁸ m/s.
Thus, a proton in a particle accelerator is traveling at a speed of 0.99c has a speed magnitude of 2.97 x 10⁸ m/s.
Learn more about speed of proton here: brainly.com/question/14663642
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