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Ivahew [28]
3 years ago
6

Titanium metal is used as a structural material in many high-tech applications such as in jet engines.

Chemistry
1 answer:
Elza [17]3 years ago
3 0

Answer:

a.Cp=0.523

b.Cp=25.02\frac{J}{mol^\circ C}

Explanation:

a. First, we solve the specific heat equation as follows:

Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523

b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:

Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}

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Explanation:

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Answer:

See explanation.

Explanation:

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In this case, we can proceed as follows:

1. Here, the undergoing chemical reaction is:

C_2H_2+\frac{5}{2} O_2\rightarrow 2CO_2+H_2O

Thus, the moles and mass of water turn out:

n_{H_2O}=20.0kgC_2H_2*\frac{1000gC_2H_2}{1kgC_2H_2} *\frac{1molC_2H_2}{26.04gC_2H_2} *\frac{1molH_2O}{1molC_2H_2}=768molH_2O\\\\m_{H_2O}=768molH_2O*\frac{18.02gH_2O}{1molH_2O}=13,840 gH_2O

2. Here, the undergoing chemical reaction is:

CaCO_3+2HCl\rightarrow CaCl_2+H_2O+CO_2

So the required moles of HCl and the yielded of water are:

n_{CaCO_3}=2.6molHCl*\frac{1molCaCO_3}{2molHCl}=1.3molCaCO_3\\\\ n_{H_2O}=2.6molHCl*\frac{1molH_2O}{2molHCl}=1.3molH_2O

3. Here, the undergoing chemical reaction is:

Al_2O_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+3H_2O

Now, we apply each mole ratio obtain:

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B.

n_{Al_2(SO_4)_3}=2.6molAl_2O_3*\frac{1molAl_2(SO_4)_3}{1molAl_2O_3} =2.6molAl_2(SO_4)_3

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3 years ago
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Answer:

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Explanation:

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In this case, since chromium is in period 4 group VIB we infer it is a transition metal which slightly reacts with acids and poorly reacts with oxygen and other oxidizing substances. Thus, in comparison with both sodium and potassium which are highly reactive even with water as they get on fire, we can say that it is less reactive than both potassium and sodium, therefore, answer is: C. chromium is a metal that is less reactive than sodium.

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IF(subscript 5)

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