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3 years ago

Titanium metal is used as a structural material in many high-tech applications such as in jet engines.

Chemistry

1 answer:

Elza [17]3 years ago

3 0

Answer:

a. $Cp=0.523$

b. $Cp=25.02\frac{J}{mol^\circ C}$

Explanation:

a. First, we solve the specific heat equation as follows:

$Q=mCp\Delta T\\Cp=\frac{Q}{m\Delta T}\\Cp=\frac{89.7J}{33.0g\times5.20^\circ C}=0.523$

b. Then, we use the molar mass of titanium to determine its molar heat capacity, as follows:

$Cp=0.523\frac{J}{g^\circ C}\times 47.87\frac{g}{mol}\\Cp=25.02\frac{J}{mol^\circ C}$

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Answer:

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2. PE = (3)(9.8)(0) = 0 J

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Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

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2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

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3 years ago

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Alex787 [66]

Answer:

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3 years ago

Classify the following as homogeneous or heterogeneous mixtures, or pure

victus00 [196]

Explanation:

Sugar - Pure substance

Magnesium Ribbon - Pure Substance

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2 years ago

While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s

nordsb [41]

Answer:

Latent heat of fusion of the substance is $6.49\times 10^{4}J/kg$

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = $1.20\times 10^{6}J$

Mass of unknown substance being melted = 18.5 kg

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3 years ago