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borishaifa [10]
3 years ago
15

What is the mass of 7.50 moles of magnesium chloride, mgcl2?

Chemistry
1 answer:
Natali5045456 [20]3 years ago
8 0
MgCl2 = 1Mg + 2Cl = 1(24.3) + 2(35.45) = 95.2g/1mole
7.50moles MgCl2 x 95.2g MgCl2 = 714g MgCl2
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A piece of brass is found to have a mass of 24.32 g. When placed in a graduated cyclinder with an initial reading of 5.60 mL the
Jobisdone [24]

Answer:

\rho=3.1g/mL

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

\rho =\frac{m}{V}

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

V=13.50mL-5.60mL=7.9mL

The density of the piece of brass turns out:

\rho =\frac{24.32g}{7.9mL}\\\\\rho=3.1g/mL

Best regards.

4 0
3 years ago
A balloon with a volume of 336.0 mL starts at a temperature of 328K. It is placed in cool water
larisa [96]

Answer:

306.43 K

Explanation:

- Use Charle's law and rearrange formula (V1/T1=V2/T2)

- Hope this helped! Let me know if you would like me to show you step-by-step how to do these types of problems.

7 0
3 years ago
How many moles of AlCl3 are formed by 1.53 moles of CuCl2?
jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

5 0
3 years ago
5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7
slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

  CO2 = 16.39 grams

  H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 =  0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

The molecular formula = 6*(CH) = C6H6

4 0
3 years ago
Help me on this science question.
mel-nik [20]
The answer is Amarillo
6 0
3 years ago
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