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4 years ago

In Linnean taxonomy, the most unique level is _____. species genus kingdom breed

Physics

2 answers:

Nookie1986 [14]4 years ago

6 0

The answer is species, I hope this helps!

dezoksy [38]4 years ago

5 0

The correct answer is A I'm doing the quiz too

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1.) What is the equation for Average Speed?

jok3333 [9.3K]

Answer:

Speed = Distance / Time

Explanation:

here you go :)

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3 years ago

Read 2 more answers

Coquina is a sedimentary rock you looked at in the lab that consists of tiny chunks of sea shells all stuck together by other mi

HACTEHA [7]

Coquina rock is deposited on the water bodies of the Earth's surface and oceans.

<u>Explanation:</u>

Coquina is nothing but a type of sedimentary rock generally limestone that is formed by the chunks of shells, trilobites, brachiopods, or other invertebrates.

Coquina is deposited on the oceans and water bodies of the Earth's surface. Coquina looks like a soft white rock; therefore it can be used in construction of buildings.

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4 years ago

Relative humidity _______.

horsena [70]

Answer: option d. gives the percentage of water molecules in the air.

Explanation:

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3 years ago

A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its

Katyanochek1 [597]

Answer:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

Explanation:

We can try writing the equation of the horizontal component of the length of the minute hand in terms of distance and the angle, that depends of time in this particular case.

The x-component of the length of the minute hand is:

$d_{x}(t)=dcos(\theta (t))$ (1)

d is the length of the minute hand (d=D/2)
D is the diameter of the clock
t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

$\theta (t)=\omega *t$ (2)

Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

$\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}$

Now, let's put this value on (2)

$\theta (t)=\frac{\pi}{30}*t$

Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

$d_{x}(t)=(D/2)cos(\frac{\pi}{30}*t)$

I hope it helps you!

6 0

3 years ago

A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time

IgorLugansk [536]

Recall that with constant acceleration,

$x_f-x_i=\dfrac{v_i+v_f}2t$

where $x_f-x_i$ is the rocket's displacment, $v_i$ is its initial velocity, $v_f$ its final velocity, and $t$ is time. So

$x_f-x_i=\dfrac{80\frac{\mathrm m}{\mathrm s}+152\,\frac{\mathrm m}{\mathrm s}}2(18\,\mathrm s)=2088\,\mathrm m$

or just 2100 m if taking significant digits into account.

8 0

3 years ago