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Dovator [93]
2 years ago
6

How many grams of nicl2∙6h2o will be used to prepare a 0. 0350 m, 500. 0 ml of nicl2 solution?

Chemistry
1 answer:
marin [14]2 years ago
3 0

The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of NiCl₂•6HO₂</h3>
  • Molarity = 0.035 M
  • Volume = 500 mL = 500 / 1000 = 0.5 L
  • Mole of NiCl₂•6HO₂ =?

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

<h3>How to determine the mass of NiCl₂•6HO₂</h3>
  • Mole of NiCl₂•6HO₂ = 0.0175 mole
  • Molar mass of NiCl₂•6HO₂ = 238 g/mol
  • Mass of NiCl₂•6HO₂ =?

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

Learn more about molarity:

brainly.com/question/15370276

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2 years ago
A set of charged plates is
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Answer:

2.39×10¯⁵ m²

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 8.08×10¯⁵ m

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The area can be obtained as follow:

q = ε₀AV/d

2.24×10¯⁹ = 8.854×10¯¹² × A × 855 / 8.08×10¯⁵

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A = 1.81×10¯¹³ / 7.75×10¯⁹

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