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3 years ago

How many grams of nicl2∙6h2o will be used to prepare a 0. 0350 m, 500. 0 ml of nicl2 solution?

Chemistry

1 answer:

marin [14]3 years ago

3 0

The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g

<h3>What is molarity? </h3>

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

<h3>How to determine the mole of NiCl₂•6HO₂</h3>

Molarity = 0.035 M
Volume = 500 mL = 500 / 1000 = 0.5 L

Mole of NiCl₂•6HO₂ =?

Mole = Molarity × Volume

Mole of NiCl₂•6HO₂ = 0.035 × 0.5

Mole of NiCl₂•6HO₂ = 0.0175 mole

<h3>How to determine the mass of NiCl₂•6HO₂</h3>

Mole of NiCl₂•6HO₂ = 0.0175 mole
Molar mass of NiCl₂•6HO₂ = 238 g/mol

Mass of NiCl₂•6HO₂ =?

Mass = mole × molar mass

Mass of NiCl₂•6HO₂ = 0.0175 × 238

Mass of NiCl₂•6HO₂ = 4.165 g

Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution

Learn more about molarity:

brainly.com/question/15370276

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