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sdas [7]
3 years ago
11

Question 1 of 20

Physics
2 answers:
ad-work [718]3 years ago
8 0

Answer

D. move a small magnet back and forth within a section of the coiled wire.

Explanation:

i put that for the test and i got it right

Tanzania [10]3 years ago
8 0

Answer:

d

Explanation: got it right

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A hydraulic cylinder causes the distance between points A and O to decrease at a constant rate of 3 inches per second. a) Determ
Ierofanga [76]

Answer:

a) The speed of the slider is 4.28 in/s

b) The velocity vector is 2.33 in/s

Explanation:

a) According to the diagram 1 in the attached image:

r_{C/A} =12*cos55i-12*sin55j\\r_{C/A}=6.883i-9.829j

Also:

v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j

If we comparing both sides of the expression:

-3+6.883w_{AC}=0\\w_{AC}=0.435rad/s

v_{C}=9.829*0.435=4.28in/s

b) According to the diagram 2 in the attached image:

r_{C/A}=12cos50i-12sin50j=7.713i-9.192j\\r_{B/C}=-3.856i+4.596j

v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j

Comparing both sides of the expression:

7.713w_{AC}-3=0\\w_{AC}=0.388rad/s\\v_{C}=3.575i

v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right]  \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2}  } =2.33in/s

6 0
3 years ago
S Problem Set<br> 2.) 6.4 x 109 nm to cm
anyanavicka [17]

Answer:

6.4\cdot 10^2 cm

Explanation:

First of all, let's convert from nanometres to metres, keeping in mind that

1 nm = 10^{-9} m

So we have:

6.4\cdot 10^9 nm \cdot 10^{-9} m/nm = 6.4 m

Now we can convert from metres to centimetres, keeping in mind that

1 m = 10^2 cm

So, we find:

6.4 m \cdot 10^2 cm/m = 6.4\cdot 10^2 cm

8 0
3 years ago
Write the nuclear equation for the alpha decay of astatine-213.
Sonbull [250]

Answer:

hope this helpes!!

Explanation:

plz mark brainliest

7 0
3 years ago
A car advertisement claims their car can go from a stopped position to moving 60 miles per hour in 5 seconds. The advertisement
ASHA 777 [7]

The advertisement is deciribing the car’s acceleration, as it gains speed when moving from 0-60.

4 0
4 years ago
Calculate the induced electric field in a 54-turn coil with a diameter of 19.5 cm that is placed in a spatially uniform magnetic
storchak [24]

Answer:

E = 3.049 N/C

Explanation:

Induced electric field = e/2 *(pi) *r

Induced electric field = e /(3.14 *19.5)  - Eq (1)

e = (pi)r^2*B/t

= 3.14 * (19.5/2*100)^2 * 0.50 T/ 0.1

= 1.867 V

Substituting this value in equation 1, we get –  

E = 1.867 V/(3.14 *19.5/100)  

E = 3.049 N/C

4 0
3 years ago
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