1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artemon [7]
3 years ago
10

A container is divided into two equal compartments by a partition. One compartment is initially filled with He at a temperature

THe; the other compartment is filled with oxygen (O2) at temperature T02. Both gases are at the same pressure. If we remove the partition and allow the gases to mix, what will be their final temperature
Chemistry
1 answer:
erik [133]3 years ago
3 0

Answer:

The final temperature of the mixture of helium and oxygen THe + O2.

Explanation:

If we remove the compartments between helium and oxygen molecule, they will not react with each other because helium is a noble gas or stable gas due to complete its outermost shell so it cannot react with oxygen. So if they donot react with each other, no heat energy is absorbed or released and the temperature of the container remains constant. Both the molecules remain suspended in the air and donot react with each other.

You might be interested in
HELPPP PLEASE!!!!!!!!!!!!!
Naddik [55]

Answer:

<h2>The ans is bery simple it is point a </h2>
3 0
3 years ago
What does it mean to have a “controlled” experiment?
Lena [83]

A controlled experiment is simply an experiment in which all factors are held constant except for one: the independent variable. A common type of controlled experiment compares a control group against an experimental group. All variables are identical between the two groups except the factor being tested.

hope this helps :)

if not comment and ill give you something different

8 0
3 years ago
Read 2 more answers
A chemist adds of a iron(III) bromide solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the che
vaieri [72.5K]

Answer:

0.246 kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:

0.3700 L × 2.25 mol/L = 0.833 mol

The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:

0.833 mol × 295.56 g/mol = 246 g

1 kilogram is equal to 1000 grams. Then,

246 g × (1 kg/1000 g) = 0.246 kg

3 0
4 years ago
You start out with 800 moles of a radioactive substance. After 24 hours, 100 moles remain. What is the half-life of the substanc
Nookie1986 [14]

The half life of the substance is 8 hours , Option D is the correct answer.

<h3></h3>

What is Half Life ?

Half-life is the time required by an unstable element  to reduce to half of its initial value.

The term is commonly used in nuclear physics.

The formula is

\rm N(t) = \; N_{0} \;(\dfrac{1}{2} )^{\frac{t}{t_{1/2} } }

N(t)     =    quantity of the substance remaining

N ₀      =    initial quantity of the substance

t    =  time elapsed

\rm t_{1/2}    =    half life of the substance

The data given in the question is N ₀ = 800 moles , N(t)= 100 , t= 24 hours

\rm t_{1/2} =\; ?

Substituting values in the equation

\rm 100 = \; 800 \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }

\rm \dfrac{100}{800}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm \dfrac{1}{8}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm (\dfrac{1}{2})^{3}  =  \;(\dfrac{1}{2} )^{\frac{24}{t_{1/2} } }\\\\\rm 3=\dfrac{24}{t_{1/2} }\\\\t_{1/2}= \dfrac{24}{3}\\\\t_{1/2} = 8 hours

Therefore half life of the substance is 8 hours , Option D is the correct answer.

To know more about Half Life

brainly.com/question/24710827

#SPJ2

3 0
2 years ago
Calculate the atomic radius, in nm, of the BCC Metal above utilizing the density and the atomic weight provided by examination b
andre [41]

Answer:

radius = 0.2195 nm

Explanation:

l = 2r

r = 0.439/2 = 0.2195

7 0
3 years ago
Other questions:
  • What is the volume of a solid with a mass of 17.4 g and a density of 0.934 g /cm cubed?
    10·1 answer
  • Covert from cm to m plz and thank u:);)
    15·2 answers
  • Solar panels use which of the following energy sources to generate electricity?​
    8·1 answer
  • PLEASE ANSWER CORRECTLY PLEASE
    13·1 answer
  • Suppose 6.54g of potassium bromide is dissolved in 50.mL of a 0.70 M aqueous solution of silver nitrate. Calculate the final mol
    6·1 answer
  • How many molecules are there in 75.0 grams of phosphorus trichloride plzz helpp
    11·1 answer
  • 4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
    6·1 answer
  • Volcanoes tend to erupt at places where
    9·2 answers
  • (Gr.7science)
    5·2 answers
  • PLEASEEE HELPPPPP ASAPPPPPP!!!!
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!