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Elan Coil [88]
3 years ago
11

What moon phase occurs 3-4 days after a waning gibbous?

Physics
1 answer:
rewona [7]3 years ago
8 0

The "waning gibbous" begins immediately after the Full Moon and lasts about a week.

At the end of the week, the moon is no longer gibbous, but it's still waning.  At the instant it's exactly half-illuminated, it's called "Third Quarter", and then it continuous to wane for another week.

So 3 to 4 days after the END of the waning gibbous phase, it's a Waning Crescent. It still has another 3 to 4 days of waning to go, before it wanes away to nothing and we have the next New Moon.

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What is the reaction for P₄ + 5 O₂ --> 2 P₂O₅
mixas84 [53]

Answer:

Combination or synthesis

Explanation:

The reaction is a combination or synthesis reaction in which two or more substances combines to give a single product.

In such a reaction there is formation of compounds from the union of their constituent elements.

 The driving force for such reactions is the large and negative heat of formation of the product.

So, this is a combination reaction.

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True or false elliptical galaxies are made up of old stars containing small amount of gas
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True, They contain old stars and posses little gas or dust
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A .5 kg toy train car moving forward at 3 m/s collides with and sticks to a .8 kg toy car that is traveling at 2 m/s what is the
Viktor [21]
Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
m_{1} * v_{1} + m_{2} * v_{2} = m_{1} * v'_{1}+ m_{2} * v'_{2}

In case of perfectly inelastic collision v'1 and v'2 are same.

We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x

0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
4 0
3 years ago
During which type of collision is none of the energy converted to heat
Gre4nikov [31]
This would be typical of an elastic collision.
4 0
3 years ago
Read 2 more answers
I'm trying to find the potential energy of a planet using formula G M(sun) x m(planet) / r. I have given G - newton's graviation
ludmilkaskok [199]

Answer:

-5.39\times10^{33} J

Explanation:

Potential energy =

-\frac{GMm}{r}\\=-\frac{6.67\times10^{-11}\times1.99\times10^{30}\times5.97\times10^{24}}{147/1\times10^{9}}\\=-5.39\times10^{33} J

7 0
2 years ago
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