A 2.70-m-long pole is balanced vertically on its tip. It starts to fall and its lower end does not slip. Part A What will be the

Question

3 years ago

7

speed of the upper end of the pole just before it hits the ground? [Hint: Use conservation of energy.]

1 answer:

valkas [14] · Answer 1 · 2022-04-13T14:28:57+03:00

Answer:

v = 7.27 m / s

Explanation:

We will use energy conservation at two points, the highest and the lowest

initial. Highest point

Em₀ = U

Em₀ = m g y

final. Lowest point

we set the reference system at this point so that the potential energy is zero

$Em_{f}$ = K

$Em_{f}$ = ½ m v²

how energy is conserved

Em₀ = $Em_{f}$

mg y = ½ m v²

v = √2 gy

v = √ (2 9.8 2.7)

v = 7.27 m / s