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____ [38]
4 years ago
9

What is the rate for the second order reaction Products when [A] = 0.371 M? (k = 0.761 M's")​

Chemistry
1 answer:
AlekseyPX4 years ago
6 0

Given :

Concentration of product [A] = 0.371 M .

Rate constant , R = 0.761\  M^{-1}t^{-1} .

To Find :

The rate for the reaction .

Solution :

We know , for second order reaction , rate is given by :

r=k[A]^2\\\\r=0.761\times 0.371^2\ M/t\\\\r=0.10\ M/t

Therefore , the rate for the second order reaction is 0.1 M/t .

Hence , this is the required solution .

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What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is K_{2}SO_{4} thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass

Putting the values,

n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol

Thus, number of moles of  K_{2}SO_{4} will be 0.1061\times 0.5=0.053 mol.

The volume of solution is 225 mL, converting this into L,

1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

Therefore, concentration of potassium sulfate solution is 0.236 M.


4 0
3 years ago
Your sick puppy is diagnosed with roundworms. They grow inside of the puppy. What type of symbiotic relationship do the puppy an
Ratling [72]
D. Parasitism , the roundworm benefits from the relationship, but the puppy is harmed
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What element has 2 electrons in its outermost energy level and is in the 2nd period on periodic table?
Olegator [25]
Be-beryllium have 2 electrons and it is in the 2 nd period
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3 years ago
A certain gas at 2oC and 1.00 atm pressure fills a 4.0 container. What volume will the gas occupy at 100oC and 780 torr pressure
artcher [175]

The final volume V₂=4.962 L

<h3>Further explanation</h3>

Given

T₁=20 + 273 = 293 K

P₁= 1 atm

V₁ = 4 L

T₂=100+273 = 373 K

P₂=780 torr=1,02632 atm

Required

The final volume

Solution

Combined gas law :

P₁V₁/T₁=P₂V₂/T₂

Input the value :

V₂=(P₁V₁T₂)/(P₂T₁)

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3 years ago
CH3OH can be synthesized by the reaction:
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Answer:

5

Explanation:

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