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____ [38]
4 years ago
9

What is the rate for the second order reaction Products when [A] = 0.371 M? (k = 0.761 M's")​

Chemistry
1 answer:
AlekseyPX4 years ago
6 0

Given :

Concentration of product [A] = 0.371 M .

Rate constant , R = 0.761\  M^{-1}t^{-1} .

To Find :

The rate for the reaction .

Solution :

We know , for second order reaction , rate is given by :

r=k[A]^2\\\\r=0.761\times 0.371^2\ M/t\\\\r=0.10\ M/t

Therefore , the rate for the second order reaction is 0.1 M/t .

Hence , this is the required solution .

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Four hundred kg/h of Steam from a low pressure turbine at 12.5 atm. and 250 C goes into a feed water heater which preheats the w
Nitella [24]

Explanation:

According to the heat relationship,

    Heat given by steam = heat taken by water

Hence,    (mC_{p} \Delta T)_{steam} = (mC_{p} \Delta T)_{water}

where, C_{p} = specific heat

Value of C_{p}_{steam} at 250^{o}C and 12.5 atm is 2.326 kJ/Kg^{o}C.

And, C_{p}_{steam} at 200^{o}C and 12.5 atm is 2.743 kJ/Kg^{o}C.

Therefore, average C_{p}_{steam} = \frac{2.326 kJ/Kg^{o}C + 2.743 kJ/Kg^{o}C}{2}

                                          = 2.5345 kJ/Kg^{o}C

As the given data is as follows.

      m_{steam} = 400 kg/hr, \Delta T_{steam} = 250^{o}C - 200^{o}C = 50^{o}C, m_{water} = 500 kg/hr

            C_{p}_{water} = 4.186 kJ/kg^{o}C

Hence, putting the given values into the above formula as follows.

           (mC_{p} \Delta T)_{steam} = (mC_{p} \Delta T)_{water}

  (400 \times 2.5345 kJ/kg^{o}C \times 50^{o}C)_{steam} = (500 kg \times 4.186 kJ/kg^{o}C \Delta T)_{water}

                \Delta T_{water} = 24.2^{o}C

As we know that, \Delta T_{water} = T_{2} - T_{1}

                             T_{2} - 20^{o}C = 24.2^{o}C

                            T_{2} = 44.2^{o}C

Thus, we can conclude that the new temperature of water is 44.2^{o}C.

3 0
4 years ago
10pt if given the correct answer I will mark you as brainliest
diamong [38]

Answer:

C

Explanation:

4(Al)+3(O2)==2(Al2O3)

Also, i'm in sixth grade just took a leson on a text book so may be wrong but i'm prety sure it's the correct nswer because x(Al)+y(O2) can not make hydregen for the h2o and for b, al+so2 = al2O3 makes sense but where did the sulfer go?

3 0
3 years ago
Read 2 more answers
Give me a hand,Solve this problem,Need everyone's help​
elixir [45]

Answer:

A. 8.8 g.

B. 5.3 g.

C. 449 g.

Explanation:

A. Determination of the mass of CO2.

Mole of CO2 = 0.2 mole

Molar mass of CO2 = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO2 =?

Mole = mass /Molar mass

0.2 = mass of CO2 /44

Cross multiply

Mass of CO2 = 0.2 × 44

Mass of CO2 = 8.8 g

B. Determination of the mass of Na2CO3.

Mole of Na2CO3 = 0.05 mole

Molar mass of Na2CO3 = (2×23) + 12 + (3×16)

= 46 + 12 + 48

= 106 g/mol

Mass of Na2CO3 =?

Mole = mass /Molar mass

0.05 = mass of Na2CO3 /106

Cross multiply

Mass of Na2CO3 = 0.05 × 106

Mass of Na2CO3 = 5.3 g

C. Determination of the mass of Fe(OH)2.

Mole of Fe(OH)2 = 5 moles

Molar mass of Fe(OH)2 = 55.8 + 2(16 + 1)

= 55.8 + 2(17)

= 55.8 + 34

= 89.8 g/mol

Mass of Fe(OH)2 =?

Mole = mass /Molar mass

5 = mass of Fe(OH)2/89.8

Cross multiply

Mass of Fe(OH)2 = 5 × 89.9

Mass of Fe(OH)2 = 449 g.

8 0
3 years ago
DA gas has a volume of 4.00 L at 0 degrees Celsius. What final temperature, in degrees Celsius, is needed to change the volume o
Sholpan [36]
D 50.O ML IS THE ANSWER

6 0
4 years ago
Based on the following information, Cl2(g) + 2 e- → 2 Cl-(aq) E° = + 1.36 V Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V which of the
Alex

Answer:

D) Mg(s)

Explanation:

We are given:

E^o_{(Cl_2/Cl^-)}= 1.36V\\E^o_{(Mg^{2+}/Mg)}=-2.37V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, chlorine will undergo reduction reaction will get reduced.  Magnesium will undergo oxidation reaction and will get oxidized.

<u>Reducing agents are the species which reduces others and oxidizes itself. Thus, Magnesium will be the strongest reducing agent.</u>

7 0
4 years ago
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