What is the rate for the second order reaction Products when [A] = 0.371 M? (k = 0.761 M's")
1 answer:
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Answer: d) -705.55 kJ
Explanation:
Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.
Reversing the reaction, changes the sign of
On multiplying the reaction by , enthalpy gets half:
Thus the enthalpy change for the given reaction is -705.55kJ
Answer:
the activation energy Ea = 179.176 kJ/mol
it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.
Explanation:
From the given information
Thus;
Because at 113.0°C; the rate is 7 time higher than at 100°C
Hence:
1.9459 =
Ea = 179.176 kJ/mol
Thus; the activation energy Ea = 179.176 kJ/mol
b)
here;
where ;
Now;
t = 7.0245 mins
Therefore; it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.