Answer:
To hit the ground, it will take the watch:
Step-by-step explanation:
Making use of the provided equation:
- <u>h (t) = - 16t ^ 2 + initial height
</u>
Which can be modified specifically for this case:
- <u>h (t) = - 16t ^ 2 + 6400 feet.
</u>
Time must be replaced a certain number of times until the value is zero, this can be done one by one, but since it would be too many iterations I will show you some examples and what you could deduce in each case.
<em>With t = 1 second:
</em>
- h (1) = - 16 (1) ^ 2 + 6400 feet = 6384 feet (only the watch has dropped 16 feet)
<em>With t = 7 seconds:
</em>
- h (7) = - 16 (7) ^ 2 + 6400 feet = 5616 feet (has fallen 784 feet)
<em>With h = 15 seconds:
</em>
- h (15) = - 16 (15) ^ 2 + 6400 ft = 2800 feet (3600 ft has fallen, it is not long)
<em>With h = 21 seconds:
</em>
- h (21) = - 16 (21) ^ 2 + 6400 feet = -656 feet (When obtaining a negative number, it is understood that the time was too long, therefore a shorter time must be taken)
<em>With h = 20 seconds:
</em>
- <u>h (20) = - 16 (20) ^ 2 + 6400 feet = 0 feet
</u>
<u>Since with 20 seconds the exact value of zero is obtained, this time is the exact time it would take the watch to fall to the ground</u>, since when this time is reached the height (h) will be zero, that is, at ground level .
For this case we have the following variables:
x: number of hours that it takes Mr. David to complete a job working alone.
y: number of hours it takes Mr. Ludwing to complete a job working alone.
k: number of hours it takes for both of them to do a job working together.
We now write the equation that models the problem.
To do this, we must add the work rate per hour of each and equal to the rate of work per hour of both.
We have then:
Answer:
The algebraic expression that models the problem is:
hey I just met you and this is crazy but here's my number so call me baby
Answer:
25 days old
Step-by-step explanation:
7 days = 1 week
3 x 7 = 21
21 + 4 = 25
25 days old
Answer:
2=-8-x
10=-x
hope it helps you to please mark me brainliest
