Question

A 1423 kg car is traveling down the road at 105.0 km/h. while traveling at this rate of speed, what is the kinetic energy of this vehicle in kilojoules?

Answer 1

The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

Further explanation

Let's recall Kinetic Energy formula as follows:

$Ek = \frac{1}{2}mv^2$

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

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Given:

mass of car = m = 1423 kg

speed of car = v = 105.0 km/h = 29¹/₆ m/s

Asked:

kinetic energy of car = Ek = ?

Solution:

We will use Kinetic Energy formula as follows:

$Ek = \frac{1}{2}mv^2$

$Ek = \frac{1}{2}(1423)(29\frac{1}{6})^2$

$Ek \approx 6.053 \times 10^5 \texttt{ Joules}$

$Ek \approx 6.053 \times 10^2 \texttt{ kiloJoules}$

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Conclusion:

The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

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Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Answer 2

605.3 kilojoules First, convert the 105.0 km/h to m/s 105.0 km/h * 1000 m/km / 3600 s/h = 29.16666667 m/s Now calculate the energy using the E = 0.5 M V^2 formula E = 0.5 * 1423 kg * (29.16666667 m/s)^2 E = 711.5 kg * 850.69 m^2/s^2 E = 605269.0972 (kg m^2)/s^2 E = 605269.0972 J E = 605.2690972 kJ Rounding to 4 significant figures gives 605.3 kilojoules