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3 years ago

The biosphere of the earth is made up of _______compounds. A. Inorganic B. Organic

Chemistry

2 answers:

ale4655 [162]3 years ago

8 0

Answer:

Organic :)

Explanation:

KATRIN_1 [288]3 years ago

5 0

Answer:

Explanation:

When we say "biosphere", we're referring to the atmosphere, geosphere, lithosphere and hydrosphere, and everything in them. You've probably heard of these in class as the "pillars of Earth" or the "pillars of our planet". In other words, when we talk about biosphere we're talking about life.

Organic compounds are all of the compounds that contain carbon, C, in them. You might know that CHNOPS* are the "7 molecules of life", and you might have noticed that Carbon stands first in the list, and that's not because it makes up a mnemonic, Carbon is indeed the most important one in many ways.

*Carbon, Hydrogen, Nitrogen, Oxygen, Phosphorus and Sulfur.

Hope it helped,

BiologiaMagister

You might be interested in

What is the percentage of water in the hydrate CoCl2 • 6H2O? Show your work.

Lelu [443]

Hello!

First you have to find the molar mass of the molecules

C = 12
O = 16
2Cl = 71
6H2O = 108

Add them up to find the total molar mass

12 + 16 + 71 + 108 = 207g/mol

Divide the amount of water by the total molar mass

108 / 207 = 0.5217

Convert this to a decimal

0.5217 = 52.17%

The answer is 52.17%

Hope this helps!

7 0

4 years ago

1.) Rust forms when Fe, O₂, and H₂O react in the balanced equation below;

valentinak56 [21]

Answer:

1.) A.) The limiting reactant is Fe.

B.) 16.17 g.

2.) 84.70 %.

Explanation:

For the balanced equation:

2Fe(s) + O₂(g) + 2H₂O(l) → 2Fe(OH)₂(s).

2.0 moles of Fe reacts with 1.0 mole of oxygen and 2.0 moles of water to produce 2.0 moles of Fe(OH)₂.

A.) Which of these reactants is the limiting reagent?

To determine the limiting reactant, we should calculate the no. of moles of reactants using the relation: n = mass/molar mass.

Suppose that water is exist in excess.

no. of moles Fe = mass/atomic mass = (10.0 g)/(55.845 g/mol) = 0.179 mol ≅ 0.18 mol.

no. of moles of O₂ = mass/molar mass = (4.0 g)/(32.0 g/mol) = 0.125 mol.

Since from the balanced equation; every 2.0 moles of Fe reacts with 1.0 mole of oxygen.

So, 0.18 mol of Fe reacts with 0.09 mol of O₂.

Thus, the limiting reactant is Fe.

The reactant in excess is O₂ (0.125 mol - 0.09 mol = 0.035 mol).

B.) How many grams of Fe(OH)₂ are formed?

Using cross multiplication:

∵ 2.0 moles of Fe produce → 2.0 moles of Fe(OH)₂.

∴ 0.18 moles of Fe produce → 0.18 moles of Fe(OH)₂.

∴ The mass (no. of grams) of produced 0.18 mol of Fe(OH)₂ = no. of moles x molar mass = (0.18 mol)(89.86 g/mol) = 16.17 g.

2.) (Using the reaction listed in question 1.) If 2.00 g Fe is reacted with an excess of O₂ and H₂0, and a total of 2.74 g of Fe(OH)₂ is actually obtained, what is the % yield?

The % yield = [(actual mass/calculated mass)] x 100.

The actual mass = 2.74 g.

We need to calculate the theoretical mass:

Firstly, we should calculate the no. of moles of reactants using the relation: n = mass/molar mass.

no. of moles Fe = mass/atomic mass = (2.0 g)/(55.845 g/mol) = 0.0358 mol ≅ 0.036 mol.

Using cross multiplication:

∵ 2.0 moles of Fe produce → 2.0 moles of Fe(OH)₂.

∴ 0.036 moles of Fe produce → 0.036 moles of Fe(OH)₂.

∴ The calculated mass (no. of grams) of produced 0.036 mol of Fe(OH)₂ = no. of moles x molar mass = (0.036 mol)(89.86 g/mol) = 3.235 g.

∴ The % yield = [(actual mass/calculated mass)] x 100 = [(2.74 g/3.235 g)] x 100 = 84.70 %.

4 0

3 years ago

Which is a strategy for preventing household fires?

Pani-rosa [81]

Answer:

Explanation:

6 0

4 years ago

Which factors affect both the solubility and rate of dissolution of a solid

klemol [59]

Temperature
Surface area
Stirring
Pressure

6 0

4 years ago

If after heating the reaction between magnesium and hydrochloric acid, the mass of the magnesium chloride and beaker is measured

Allushta [10]

Since the beaker was heated we can asume that only magnesium cloride is left in the beaker, therfore the difference between the beaker with magnesium chloride and the empty beaker give the mass of magnisium chloride:

$\text{mass MgCl}_2=massbeakerwithMgCl_2-mass\text{ emprty beaker =37.83 g - 33.95g = 3.8}8g$

7 0

1 year ago