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Ede4ka [16]
4 years ago
14

The atomic bomb detonated in 1945 produced an explosion equivalent to 18,600 tons of TNT from 5 kg of _____.

Chemistry
1 answer:
kvasek [131]4 years ago
3 0
JAPAN GOT NUKED LOL its so funny
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If a rock had a mass of 20g explain how you would fund the density
REY [17]

Answer:

you have to divide it

Explanation:

4 0
3 years ago
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use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a vel
My name is Ann [436]

Answer:

7.7439×10⁻³¹ m

Explanation:

The expression for Heisenberg uncertainty principle is:

\Delta x\times \Delta v=\frac {h}{4\times \pi\times m}

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

\Delta x\times 0.1=\frac {6.62\times 10^{-34}}{4\times \frac {22}{7}\times 0.68\times 10^{-3}}

<u>Δx = 7.7439×10⁻³¹ m</u>

8 0
4 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g)
wolverine [178]

Answer:

The correct answer is 8.10

Explanation:

Given:

A(g) + 2B(g) ↔ AB₂(g)   Kc = 59 ---- Eq. 1

A(g) + 3B(g) ↔ AB₃(g)   Kc = 478 ----- Eq. 2

We have to rearrange the chemical equations in order to obtain:

AB₂(g) + B(g) ↔ AB₃(g) Kc = ?

AB₂(g) is a reactant, so we have to use the reverse reaction of Eq. 1, in this case Kc= 1/59. Since AB₃(g) is a product, we use the forward reaction of Eq.2, and the constant is the same: Kc= 478.  The following is the sum of rearranged chemical equations, and the compounds in bold and italic are canceled:

 AB₂(g)       ↔   <em>A(g)</em> + <em>2B(g)</em>          Kc₁= 1/59

<em>A(g)</em> + <em>3B(g)</em> ↔   AB₃(g)                  Kc₂= 478

-----------------------------------------

AB₂(g) + B(g) ↔ AB₃(g)

If we add reactions at equilibrium, the equilibrium constants Kc are mutiplied as follows:

Kc = Kc₁ x Kc₂ = 1/59 x 478 = 478/59 = 8.10

The value of the missing equilibrium constant is 8.10.

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