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stellarik [79]
3 years ago
7

Find the closest point to y in the subspace W spanned by Bold v 1 and Bold v 2. yequals[Start 4 By 1 Matrix 1st Row 1st Column 3

2nd Row 1st Column negative 1 3rd Row 1st Column 1 4st Row 1st Column 13 EndMatrix ]​, Bold v 1equals[Start 4 By 1 Matrix 1st Row 1st Column 1 2nd Row 1st Column negative 2 3rd Row 1st Column negative 1 4st Row 1st Column 2 EndMatrix ]​, Bold v 2equals[Start 4 By 1 Matrix 1st Row 1st Column negative 4 2nd Row 1st Column 1 3rd Row 1st Column 0 4st Row 1st Column 3 EndMatrix ]The closest point to y in W is the vector [Start 4 By 1 Matrix 1st Row 1st Column nothing 2nd Row 1st Column nothing 3rd Row 1st Column nothing 4st Row 1st Column nothing EndMatrix ].

Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the detailed step by step solution of the given problem.

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Find the distance between points B and N.
Gekata [30.6K]

Answer:

5

Step-by-step explanation:

b is at 15

n is at 10

hence -15 - -10=5

positive 5 btw

5 0
2 years ago
Verify the trigonometric identities
snow_lady [41]
1)

here, we do the left-hand-side

\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2
\\\\\\\
[sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)]
\\\\\\
2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2

2)

here we also do the left-hand-side

\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x)
\\\\\\
\cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)}
\\\\\\
\cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)

3)

here, we do the right-hand-side

\bf \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}=\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}
\\\\\\
\cfrac{csc(x)-tan(x)}{sec(x)+cot(x)}\implies \cfrac{\frac{1}{sin(x)}-\frac{sin(x)}{cos(x)}}{\frac{1}{cos(x)}-\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{cos(x)-sin^2(x)}{sin(x)cos(x)}}{\frac{sin(x)+cos^2(x)}{sin(x)cos(x)}}
\\\\\\
\cfrac{cos(x)-sin^2(x)}{\underline{sin(x)cos(x)}}\cdot \cfrac{\underline{sin(x)cos(x)}}{sin(x)+cos^2(x)}\implies \cfrac{cos(x)-sin^2(x)}{sin(x)+cos^2(x)}
8 0
3 years ago
Decrypt the word DKA if it was encrypted using an alphabetic Caesar shift cipher that starts with shift 5 (mapping A to F), and
pochemuha

Answer:

YET

Step-by-step explanation:

TO DECRYPT DKA USING THE CAESAR SHIFT CIPHER STARTING WITH 5 SHIFTS.

TO DO THIS DECRYPTION, WE'RE GOING TO LOOP THE ALPHABETS.

D = LOOPING THIS LETTER 5 TIMES, WE HAVE C - B - A - Z - Y.

SO, D IS DECRYPTED AS Y

GOING FURTHER, THE ENCRYPTION SHIFTS BY AN ADDITIONAL SPACE. THIS MEANS, IF THE FIRST "Y" WAS ENCRYPTED IN 5 SPACES TO GET D, AND AN ADDITIONAL SPACE WAS ADDED TO THE NEXT ALPHABET, IT BECOMES 6.

K IS THEN DECRYPTED AS

K = J - I - H - G - F - E

K IS DECRPYTED AS E

GOING FURTHER, THE NEXT WAS ENCRYPTED WITH AN ADDITIONAL SPACE EVEN MORE, SO, A IS DECRPYTED AS

A = Z - Y - X - W - V - U - T.

THUS, DKA IS DECRYPTED AS YET

5 0
3 years ago
Which of the following statements is true?
Margaret [11]

Answer:

c

Step-by-step explanation:

it's more a gut feeling

5 0
3 years ago
Find 15 percent of 15 percent of 15 percent of 500 how does this compare to finding 45 percent of 500?
4vir4ik [10]
Completely different...

.15*.15*.15*500

500(.15^3)=1.6875

500(.45)=225
4 0
3 years ago
Read 2 more answers
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