Person is lifting a 250 N dumbbell. The weight is 30 cm from the pivot point of the elbow. What force must be exerted five from
the elbow to lift the weight? Assume everything is perpendicular.
1 answer:
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Explanation:
see the above attachment to solve the question and get the answer.
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Answer:
T'=92.70°C
Explanation:
To find the temperature of the gas you use the equation for ideal gases:
V: volume = 3000cm^3 = 3L
P: pressure = 1250mmHg; 1 mmHg = 0.001315 atm
n: number of moles
R: ideal gas constant = 0.082 atm.L/mol.K
T: temperature = 27°C = 300.15K
For the given values you firs calculate the number n of moles:
this values of moles must conserve when the other parameter change. Hence, you have V'=2L and P'=3atm. The new temperature is given by:
hence, T'=92.70°C