Answer:
50J
Explanation:
At the top you have(A)
KE_a = O
PE_a = 100J
KE + PE = 100J
At the bottom you have (C)
KE_c= 100J
PE_c=0J
KE+PE = 100J
At point C:
You are at half the height.
We know that at H, PE =100J
PE_c = mgH
At C,
PE_c= mg (H/2) *at half the height
*m and g stay the same
Intuitively, the higher you are, the more potential energy you have.
If you decrease the height by a half, your PE will also decrease
At A:
PE_a / (mg) = H
At B:
PE_b / (mg) = H/2
to also get H on the right hand side, multiply by 2
2 (PE_b/ (mg))= H
2PE_b / (mg) = H
Ok, now that we have set up 2 equations (where H is isolated), find PE at B
AT A = AT B *This way you are saying that H = H (you compare both equations)
PE_a / (mg) = 2x PE_b / (mg)
*mg are the same for both cancel them (you can do that because of the = sign)
PE_a = 2PE_b
We know that PE_a = 100J
100J/2 = PE_b
PE at b = 50J
**FIND KE at b
We know that
KE_b + PE_b is always 100J
100J = 50J + KE_b
KE_b = 50J
Answer:
Diffusion is the movement of a molecule from an area where the molecule is in high concentration to an area where the molecule is in low concentration. Facilitated diffusion is the movement of a molecule from an area of high concentration to an area where the molecule is in low concentration. Osmosis is the diffusion (high to low concentration) of water through a semi-permeable membrane. Water moves from an area of high water molecule concentration (and lower solute concentration) to an area of low concentration (and higher solute concentration.
Hope this Helps!!!
The variety of organisms on a given area. so i’d say #2. hope this is right
A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
