Answer:
The energy which is produced by a battery is 101.1 kJ.
Explanation:
The expression for the energy in terms of voltage, current and time is as follows;
E=VIt
Here, V is the voltage, I is the current and t is the time.
It is given in the problem that a battery can provide a current of 1.80 A at 2.60 V for 6.00 hr.
Calculate the energy of the battery.
E=VIt
Convert time from hour int seconds.
t=6 hr
t=(6)(60)(60)
t=21600 s
Put I= 1.80 A, V= 2.60 V and t= 21600 s in the expression of energy.
E=(2.60)(1.80)(21600)
E= 101.1 kJ
Therefore, the energy which is produced by a battery is 101.1 kJ.
Answer:
The jumper is in freefall for 12.447 seconds.
Explanation:
Let's start by calculating how far the jumper falls.
Initial height (on cliff) = 910 m
Final height after freefall = 150 m
Distance the jumper falls in freefall = 910 - 150 = 760 m
We can now use the equation of motion below to solve for the time:
![s=u*t+\frac{1}{2} (a*t^2)](https://tex.z-dn.net/?f=s%3Du%2At%2B%5Cfrac%7B1%7D%7B2%7D%20%28a%2At%5E2%29)
here. acceleration = 9.81 m/s (due to gravity)
initial speed (u) = 0 m/s (because vertical speed is 0 at the start)
and distance (s) = 760 meters (as calculated above)
So for speed we get:
![760=0*t+0.5(9.81*t^2)](https://tex.z-dn.net/?f=760%3D0%2At%2B0.5%289.81%2At%5E2%29)
![760=4.905t^2](https://tex.z-dn.net/?f=760%3D4.905t%5E2)
t = 12.447 seconds
here in the given situation if monkey starts free fall at the same instant when veterinarian shoots towards it then we know that vertical component of motion of monkey and the dart will be same as under gravity
so here the dart will always hit the monkey because they both moves under same acceleration
so here for the angle we can use
![tan\theta = \frac{H}{L}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7BH%7D%7BL%7D)
now we have
H = 3 m
L = 87.5 m
now we will have
![tan\theta = \frac{3}{87.5}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B3%7D%7B87.5%7D)
![tan\theta = 0.034](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%200.034)
![\theta = 1.96 degree](https://tex.z-dn.net/?f=%5Ctheta%20%3D%201.96%20degree)
so angle will be 1.96 degree above the ground