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3 years ago

Please answer!! need help!!

Physics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

screw and pulley

Explanation:

because they didn't have any of the other tools in that time

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Which represents the net force

ipn [44]

Answer:

The net force is 500N downwards

Explanation:

When Haley is trying to pull an object upward. The below forces are acting on the object.

Fp = 5500N

Fg = 6000N

because the force of gravity is more than the force of the pull.

Fnet = Fg - Fp = 6000N - 5500N = 500N

And, the direction of the resultant force is the direction of the larger force.

4 0

3 years ago

Gaussian surfaces A and B enclose the same positive charge+Q. The area of Gaussian surface A is three times larger than that of

GalinKa [24]

Answer:

D) equal to the flux of electric field through the Gaussian surface B.

Explanation:

Flux through S(A) = Flux through S (B ) = Charge inside/ ∈₀

4 0

3 years ago

Consider a long rod of mass, m, and length, l, which is thin enough that its width can be ignored compared to its length. The ro

ehidna [41]

Answer:

Explanation:

The rod will act as pendulum for small oscillation .

Time period of oscillation

$T=2\pi\sqrt{\frac{l}{g} }$

angular frequency ω = 2π / T

= $\omega=\sqrt{\frac{g}{l} }$

b )

ω = 20( given )

velocity = ω r = ω l

Let the maximum angular displacement in terms of degree be θ .

1/2 m v ² = mgl ( 1 - cosθ ) ,

[ l-lcosθ is loss of height . we have applied law of conservation of mechanical energy .]

.5 ( ω l )² = gl( 1 - cos θ )

.5 ω² l = g ( 1 - cosθ )

1 - cosθ = .5 ω² l /g

cosθ = 1 - .5 ω² l /g

θ can be calculated , if value of l is given .

4 0

4 years ago

A sphere of metal has a mass of 1431 g and a diameter of 5.80 cm. What is the density of metal in g/cm3

Dmitriy789 [7]

Answer:

see below

Explanation:

You will need t find the volume of the sphere

4/3 pi r^3 divide into the mass

1431 / (4/3 pi (5.8)^3) = 14 gm /cm^3

4 0

2 years ago

a. Find the magnitude of the gravitational force (in N) between a planet with mass 6.50 ✕ 1024 kg and its moon, with mass 2.45 ✕

Vanyuwa [196]

Answer:

a. $1.70\times 10^{20} N$ b. $6.94\times 10^{-3}m/s^2$ c. $2.62\times 10^{-5} m/s^2$

Explanation:

Use Gravitational Force:

$F= G\frac{Mm}{r^2}$

Use values given to have the results.

$g=\frac{F}{m}$

Use m as the mass of the Moon. Using values of a. and m you have the answer.

$g = \frac{F}{M}$

Use M mass of the planet. Use value of a and Mass of Planet.

3 0

4 years ago