When you factor out -1, you get ...
... -(2 4/5 - 6/7)
Answer:
A = Quartile 1 = 74.725
B = Median (quartile 2) = 80.25
C = Quartile 3 = 82.125
D = Minimum = 74.1
E = Maximum = 82.7
Step-by-step explanation:
The values for the data for the average life expectancy are as follows;
North Carolina 79.6
Oregon 82
District of Columbia 77.9
Nevada 81.3
New York 82.5
Colorado 80.9
Alaska 74.9
Connecticut 82.7
Montana 74.1
Mississippi 74.2
Sorting the data we have;
74.1
74.2
74.9
77.9
79.6
80.9
81.3
82
82.5
82.7
The minimum value is 74.1
The maximum value is 82.7
The 1st quartile is the 
term or 74.725
The median 2nd quartile is the 
term and the value is 80.25
Third quartile value is the
term or 82.125.
Answer:
i think it's A
Step-by-step explanation:
For problem 1, it will be 25/100, which is equal to 25%
2) The relationship is that both, the bar model and the proportion, show that x is 1/4 of the actual amount. The bar graph is more a visual. However, in both cases, the x can be solved for to be 25%
3) The percent error for 23°C will be less since it is closer to 25°C, the actual amount. The percent error is greater for 5°C since it is farther for 25°C.
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
